数字信号处理试题
一、单项选择题(在每小题的四个备选答案中，选出一个正确答案，并将正确答案的序号填在题干的括号内。每小题2分，共20分)
1.在对连续信号均匀采样时，要从离散采样值不失真恢复原信号，则采样周期T s与信号最高截止频率f h应满足关系()。
A.T s>2/f h
B.T s>1/f h
C.T s<1/f h
D.T s<1/(2f h)
2．下列系统（其中y(n)为输出序列，x(n)为输入序列）中哪个属于线性系统？() A.y(n)=x3(n)B.y(n)=x(n)x(n+2)
C.y(n)=x(n)+2
D.y(n)=x(n2)
3．下列序列中属周期序列的为()。
A.x(n)=δ(n)
B.x(n)=u(n)
C.x(n)=R4(n)
D.x(n)=1
4．已知某序列z变换的收敛域为|z|<1，则该序列为()。
A．有限长序列B.右边序列
C.左边序列
D.双边序列
5．实序列傅里叶变换的实部和虚部分别为()。
A．偶对称和奇对称B.奇对称和偶对称
C.奇对称和奇对称
D.偶对称和偶对称
6．设点数为4的序列x(n)=2n R4(n)，y(n)为x(n)的一圆周移位：y(n)=x2(n)，则y(1)=() A．1B.2C.4D.8
7．设两有限长序列的长度分别是M与N，欲用圆周卷积计算两者的线性卷积，则圆周卷积的长度至少应取()。
A．M+N B.M+N-1
C.M+N+1
D.2(M+N)
8．计算N=2L（L为整数）点的按时间抽取基-2FFT需要()级蝶形运算。
A．L B.L/2C.N D.N/2
9．下列对IIR滤波器特点的论述中错误的是()。
A．系统的单位冲激响应h(n)是无限长的
B.结构必是递归型的
C.肯定是稳定的
D.系统函数H(z)在有限z平面（0<|z|<∞）上有极点
10．下列关于窗函数设计法的说法中错误的是()。
A.窗函数的截取长度增加，则主瓣宽度减小，旁瓣宽度减小
B.窗函数的旁瓣相对幅度取决于窗函数的形状，与窗函数的截取长度无关
C.为减小旁瓣相对幅度而改变窗函数的形状，通常主瓣的宽度会增加
D.窗函数法不能用于设计FIR高通滤波器
二、判断题(判断下列各题，正确的在题后括号内打“√”，错的打“×”。每小题2分，共10分)
1．线性系统必是移不变的。()
2．两序列的z变换形式相同则这两序列也必相同。()
3．离散傅里叶变换的特点是离散时间、离散频率。()
4．按时间抽取的基-2FFT算法的运算量等于按频率抽取的基-2FFT算法。()
5．双线性变换法是非线性变换，所以用它设计IIR滤波器不能克服频率响应混叠效应。()
三、填空题(每空2分，共20分)
1．线性移不变系统的性质有_________、结合律及_________。
2．序列R3(n)的z变换为_________，其收敛域为_________。
3．用DFT近似分析连续信号频谱时,_________效应是指DFT只能计算一些离散点上的频谱。
4．用按时间抽取的基-2FFT算法计算N=2L（L为整数）点的DFT时，每级蝶形运算一般需要_________次复数乘。
5．无限长单位冲激响应（IIR）滤波器的基本结构有直接Ⅰ型，直接Ⅱ型，_________和_________四种。
6．在FIR滤波器的窗函数设计法中，常用的窗函数有_________和_________等。
四、计算与证明题（每小题10分，共50分）
1．两序列h(n)=δ(n)+2δ(n-1)+3δ(n-2),x(n)=δ(n)+δ(n-1)，求两者的线性卷积与3点圆周卷积。
2．已知长度为N的有限长序列x(n)（0≤n≤N-1）的DFT为X(k)（0≤k≤N-1），证明
X（0）＝
Hello,world.
3．画出8点按时间抽取的基-2FFT算法的运算流图。
4．已知线性移不变系统的差分方程为
y(n)=x(n)+2x(n-1)-2x(n-2)-x(n-3)
（1）画出该系统的横截型结构图。
（2）判断对应滤波器是否具有线性相位，若是，指出属于哪一类线性相位。5．试用冲激响应不变法与双线性变换法将以下模拟系统函数变换为数字系统函数: H(s)=
Hello,world.
其中抽样周期T=1s。
一、完形填空（共1道小题，共50.0分） 1.Once, three fishes lived in a pond. One evening, some ___1___ passed by the pond and saw the fishes. “This pond is full of fish”, they told each other __2___. “We have never fished here before. We must come back tomorrow morning with our ___3___ and catch these fish!” So saying, the fishermen left. When the eldest of the three fishes ___4___ this, he was troubled. He called the other fishes together and said, “Did you hear ___5___ the fishermen said? We must leave this pond at once. The fishermen will return tomorrow and kill us all!” The second of the three fishes agreed. “You are right”, he said. “We must leave the pond.” But the ____6___ fish laughed. “You are worrying without reason”, he said. “We have lived in this pond all our lives, and no fisherman has ever come here. Why should these men return? I am not going ___7____ - my luck will keep me safe.” The eldest of the fishes left the pond that ___8____ evening with his entire family. The second fish saw the fishermen ____9___ in the distance early next morning and left the pond at once with all his family. The third fish refused to leave even then. The fishermen ____10___and caught all the fish left in the pond. The third fish's luck did not help him - he too was caught and killed. (232字) a. A.fishersman B.fisherman C.fishermans D.fishermen 学生答案: D; 标准答 案: D b. A.excitedly B.excited C.excite
《数字信号处理》课程教学大纲 一、课程编号：1100020 二、课程名称：数字信号处理 ( 64学时) Digital Signal Processing 三、课程教学目的 数字信号处理是现代信息处理和传输的基础课程之一，已经成为信号和信息处理、通信和电子、计算机科学和技术等专业的学生需要学习和掌握的基本知识。 本课程以离散时间信号与系统作为对象，在介绍经典理论的基础上，适当引入了现代信号处理的理论与方法以及Matlab仿真分析软件。通过本课程的学习，使得学生能够掌握确定性离散时间信号的频谱分析原理及快速实现方法，数字滤波器的设计及实现方法。使学生能够利用计算机技术来进行数字信号的处理，并根据实际需要分析、设计数字滤波系统。 本课程是进一步学习数字通信、图像处理、随机数字信号处理、无线通信、多媒体通信等专业课程的先修课程。 四、课程教学基本要求 1．掌握离散时间信号和系统的基本标识方法 2．掌握离散时间系统的基本特性、Z变换以及离散时间信号的傅立叶变换（DTFT） 3．掌握离散傅立叶变换（DFT）以及离散傅立叶变换的快速算法（FFT） 4．掌握数字滤波器的设计方法和结构 5．了解多速率信号处理的基本内容 五、教学内容及学时分配（含实验） 理论教学（56学时） 1．绪论2学时数字信号处理的特点、实现和应用 Matlab简介 2．离散时间系统的基本特性及流图10学时抽样与重建 离散系统及其普遍关系 信号流图及Mason公式 离散时间信号的傅立叶变换 Z变换及Z反变换（留数法）
Z变换与拉普拉斯、傅立叶变换的关系 离散系统的频域分析 3．离散傅立叶变换及其快速实现14学时DFS的定义及性质 DFT的定义、性质及应用 基2时间抽选法FFT 基2频率抽选法FFT 基4时间抽选法FFT IDFT的快速算法 FFT应用（线性卷积的快速计算、CZT变换） 4．IIR数字滤波器的设计和实现12学时滤波器概述 模拟滤波器的设计 模拟滤波器的数字仿真 冲激响应不变法和双线性变换法的设计 IIR滤波器的频率变换设计 IIR数字滤波器的计算机辅助设计 IIR 滤波器的实现结构 5．FIR数字滤波器的设计10学时线性相位FIR滤波器的条件和特性概述 窗函数法 频率取样法 FIR数字滤波器的优化设计 FIR数字滤波器的实现结构 6．多速率信号的处理基础8学时抽取和内插的时域和变换域描述 抽取滤波器和内插滤波器 多相分解 正交镜像滤波器组 双通道滤波器组 实验教学（8学时）
北邮网络学院工商管理英语练习题答案 一、阅读理解（共1道小题，共25.0分） 1 (错误)People are so busy these days that many have no time to cook. This is a problem because many families love home cooking! A family meal brings everyone together. In some families, meals are often the only time everyone sees each other at the same time. Another reason people enjoy home cooking is that it is often a way of showing love. A parent who makes some cookies is not just satisfying a child's sweet tooth. She or he is sending a message. The message says, "I care about you enough to spend an hour making cookies that you will eat up in 15 minutes if I let you." There is also something about the smell of home cooking. The smell of home cooking pleases people of all ages. It makes most of us feel good and loved --- even if we are the ones doing the cooking! Next time you smell a cake being cooked, stop for a moment and pay attention to your mood（心情）. 1. Why do few people cook now? 1They have no time. 1They can buy food. 1Many people don?t like cooking. 1They d on?t like family meals. A parent spends an hour making cookies____. 1just to satisfy her or his child?s sweet tooth 1only to send a message 1to let a child eat up in 15 minutes 1often to show her or his love The writer thinks the smell of home cooking _____. 1makes us happy 1makes us be interested in cooking 1makes us pay attention to our mood 1makes us love others What?s the main idea of this passage? 1Family meals are important. 1How to make cookies. 1People are too busy to cook 1Homemade cookies taste better. Which of the following statements is NOT true according to the passage? 1There are quite a few reasons that people love home cooking. 1It becomes a problem that most families love home cooking. 1The smell of home cooking makes most of us feel good. 1 A family meal can bring the family members together. 试题分值：25.0 得分：[5, 5, 0, 5, 0] 提示：[1]A.细节题。本题问“为何现在没有多少人愿意下厨了?”中心词是“few people cook”。
一、阅读理解（共1道小题，共50.0分） 1.Robert Bruce was a famous Scottish general. In the early 14th century he tried to drive the English out of Scotland, but he was not successful because the English were too strong. Finally, Bruce had to run away and hide in a cave. One day, he lay in his cave thinking of the sad state of Scotland. A spider began to make a web above his head. Simply to pass the time, Bruce broke the web. Immediately the spider began to make a new one. Six times Bruce broke the web and six times the spider immediately made a new one. Bruce was surprised at this. He told himself that he would break the web a 7th time. If the spider made a new one, it would be a good lesson to him, for like the spider, he had been defeated six times. Bruce then broke the web. Again the spider made a new one. From this simple fact, Bruce became encouraged. He again got an army together. This time he was successful and drove the English out of Scotland. 1. Who was Robert Bruce? A. He was an English general. B. He was a Scottish general. C. He was a spider researcher D. He was a biologist from Scotland. 2. Why did Bruce hide in a cave? A. Because he was defeated by the English. B. Because he was afraid of the English army. C. Because he was looking for spiders D. Because he was badly injured in the battle. 3. In the beginning he broke the spider web just because______.
一、阅读理解（共1道小题，共25.0分） 1. A pretty, well―dressed young lady stopped a taxi in a big square, and a said to the driver, "Do you see that young man at the other side of the square?" "Yes," said the taxi driver. The young man was standing outside a restaurant and looking impatiently (不耐烦地) at his watch every few seconds. "Take me over there," said the young lady. There were a lot of cars and buses in the square, so the taxi driver asked, "Are you afraid to cross the street?" "Oh, no!" said the young lady. "But I promised that I would meet the young man for lunch at one o' clock, and it is now a quarter to two. If I arrive in a taxi, it will at least seem as if I had tried not to be late." 1.How did the young woman get to the square? A.She arrived in a taxi. B.She drove there in a car. C.She got there by bus. D.The story doesn't tell us. 2.Why did the lady stop the taxi? A.Because she didn't want to be late for her appointment (约会). B.Because she wanted to get out of the taxi. C.Because she wanted to go to the restaurant in it. D.Because she was afraid of walking across the street. 3.The young man at the other side of the square_______. A.had probably been waiting for a long time B.had some problem with his watch C.was probably a waiter of the restaurant D.was someone the young lady didn't want to see 4.The young lady was_______. A.clever at making excuse B.not late at all C.45 minutes earlier D.15 minutes late 5.Had she tried not to be late? A.Yes, she had tried her best. B.No, she was just pretending that she had tried. C.Yes, she had tried but she was still late. D.No, she thought being late was better than being early.
北京邮电大学随机信号分析与处理综合练习题 一、判断题： 1. 设()X t 和()Y t 是相互独立的平稳随机过程，则它们的乘积也是平稳的。 2.()X t 为一个随机过程，对于任意一个固定的时刻i t ，()i X t 是一个确定值。 3.设X 和Y 是两个随机变量，X 和Y 不相关且不独立，有()()()D X Y D X D Y +=+。 4.一般来说，平稳正态随机过程与确定性信号之和仍然为平稳的正态过程。 5.设()X t 是不含周期分量的零均值平稳随机过程，其自相关函数为()X R τ，从物 理概念上理解，有lim ()0X R ττ→∞ =。 6. 对于线性系统，假设输入为非平稳随机过程，则不能用频谱法来分析系统输出随机过程的统计特性。 7. 若随机过程X (t )满足，与t 无关，则X (t )是广义平稳（宽平稳）过程。 8. 随机过程的方差表示消耗在单位电阻上瞬时功率的统计平均值。 9. 广义循环平稳的随机过程本身也是一种广义平稳的随机过程。 10. 高斯白噪声经过匹配滤波器后仍然为高斯白噪声。 二．选择填空 1．对于联合平稳随机过程()X t 和()Y t 的互相关函数()XY R τ，以下关系正确的是 （1）。 （1）A ．()()XY XY R R ττ-= B.()-()XY YX R R ττ-=
C.)()(ττYX XY R R =- D.)()(ττXY XY R R -=- 2.随机过程X(t)的自相关函数满足1212(,)()()0X X X R t t m t m t =≠，则可以断定1()X t 和2()X t 之间的关系是（2）。 （2）A.相互独立B.相关C.不相关D.正交 3．两个不相关的高斯随机过程)(t X 和)(t Y ，均值分别为X m 和Y m ，方差分别为2X σ和2Y σ，则) (t X 和)(t Y 的联合概率密度为（3）。 （3）A ．2222()()(,)22X Y X Y x m y m f x y σσ????--??=-+?????????? B.2222()()1 (,)exp 222X Y X Y X Y x m y m f x y πσσσσ????--??=-+?????????? C.2222()()(,)2()X Y X Y x m y m f x y σσ??-+-=-??+?? D.2222()()1 (,)exp 22()X Y X Y X Y x m y m f x y πσσσσ??-+-=-??+?? 4.设()sin()()c X t A t n t ω=+，其中()()cos()()sin()c c s c n t n t t n t t ωω=-是零均值平稳窄带高斯噪声，A 是不等于0的常数，则()X t 的包络服从（4），()X t 的复包络服从（5）。 （4）A.莱斯分布B.瑞利分布C.高斯分布D.均匀分布 （5）A.莱斯分布B.瑞利分布C.高斯分布D.均匀分布 5.设()N t 是平稳随机过程，其功率谱密度为()N G ω，定义()0()()sin X t N t t ωθ=+，θ在0到2π之间均匀分布，则()X t 的平均功率谱密度为（6）。
数字信号处理软件实验 MATLAB 仿真 2015年12月16日
实验一：数字信号的 FFT 分析 ● 实验目的 通过本次实验，应该掌握： (a) 用傅立叶变换进行信号分析时基本参数的选择。 (b) 经过离散时间傅立叶变换（DTFT ）和有限长度离散傅立叶变换（DFT ）后信号频谱上的区别，前者 DTFT 时间域是离散信号，频率域还是连续的，而 DFT 在两个域中都是离散的。 (c) 离散傅立叶变换的基本原理、特性，以及经典的快速算法（基2时间抽选法），体会快速算法的效率。 (d) 获得一个高密度频谱和高分辨率频谱的概念和方法，建立频率分辨率和时间分辨率的概念，为将来进一步进行时频分析（例如小波）的学习和研究打下基础。 (e) 建立 DFT 从整体上可看成是由窄带相邻滤波器组成的滤波器组的概念，此概念的一个典型应用是数字音频压缩中的分析滤波器，例如 DVD AC3 和MPEG Audio 。 ● 实验内容及要求 ? 离散信号的频谱分析 设信号 此信号的0.3pi 和 0.302pi 两根谱线相距很近，谱线 0.45pi 的幅度很小，请选择合适的序列长度 N 和窗函数，用 DFT 分析其频谱，要求得到清楚的三根谱线。 ? DTMF 信号频谱分析 用计算机声卡采用一段通信系统中电话双音多频（DTMF ）拨号数字 0～9的数据，采用快速傅立叶变换（FFT ）分析这10个号码DTMF 拨号时的频谱。 00010450303024().*cos(.)sin(.)cos(.)x n n n n ππππ=+--
●MATLAB代码及结果 ?离散信号的频谱分析 clf; close all; N=1000; n=1:1:N; x=0.001*cos(0.45*n*pi)+sin(0.3*n*pi)-cos(0.302*n*pi-pi/4); y=fft(x,N); mag=abs(y); w=2*pi/N*[0:1:N-1]; stem(w/pi,mag); axis([0.25 0.5 0 2]); xlabel('频率'); ylabel('X(k)'); grid on;
北邮大学英语2答案 【精选】
一、完形填空（共1道小题，共50.0分） 1.(错误) I first saw the baby panda when she was only 10 days old. She looked like a white mouse. We ____1___her Xi Wang. It means “hope”. When Xi Wang was born, she weighed____2___100 grams. Xi Wang drank her mothe r’s milk for as much as 14 hours a day. When she was six months old, she started to eat bamboo shoots (嫩芽) and ____3____. Eight months later, she was not a small baby any more. She grew into a____4___young panda and weighed 35 kilos. When Xi Wang was 20 months old, she had to look after herself _____5___ her mother had another baby. ____6_____, it is very difficult for pandas to live in the wild. Here are some of the _____7____that pandas like Xi Wang may have in the future. If hunters catch a panda, they will kill it for its fur. If farmers____8____trees and forests, pandas will have no place to live in. When mothers leave baby pandas alone, people will often take them away. People think that the baby pandas need ____9_____. If pandas are in danger, we should try our best to protect them. If we do____10_____, soon there will be no more pandas in the world!?? a. A.made B.called C.told D.kept 学生答案: B; 标准答 案: B b. A.quite
、完形填空（共1道小题，共50.0分） 1. Many students find the experience of attending university lectures to be a confusing and frustrating experience. The lecturer speaks for one or two hours, perhaps 1 the talk with slides, writing up important information on the blackboard, 2 reading material and giving out assignment. The new student sees the other students continuously writing on notebooks and 3 what to write. Very often the student leaves the lecture with notes which do not catch the main points and 4 become hard even for the students to understand. Most institutions provide courses which assist new students to develop the skills they need to be 5 listeners and note-takers. If these are unavailable, there are many useful study-skills guides which 6 learners to practice these skills independently. In all cases it is important to 7 the problem before actually starting your studies. It is important to acknowledge that most students have difficulty 8 acquiring the language skills required in college study. One way of 9 these difficulties is to attend the language and study-skills classes which most institutions provide throughout the academic year. Another basic strategy is to find a study partner 10 it is possible to identify difficulties, exchange ideas and provide support. a. A. illustrating B. which C. wonders D. effective E. distributing 学生答人标准答A A; … A; 案：’案：’ b. A. illustrating B. which C. wonders D. effective E. distributing 学生答匚标准答匚 案：巳案：巳
√1. Mrs Smith warned her daughter ______ after drinking. 正确答案：A 题目注释 A . never to drive B . to never drive C . never driving D . never drive √2. She was glad to see her child well______________ . 正确答案：B 题目注释 A . take care of B . taken care of C . taken care D . taking care or √3. Don't let him ________ you_____for a long time. 正确答案：C 题目注释 A . to make, wait B . make, to wait C . make, wait D . to make, to wait √4. The sentence needs_____________ . 正确答案：C 题目注释 A . to improve B . improve C . improving D . improved √5. Napoleon spoke so loudly as to ________ in front of his soldiers. 正确答案：B 题目注释 A . hear B . be heard
C . listen D . be listened √6. Now the need_______ other people's language is becoming greater and greater. 正确答案：A 题目注释 A . to learn B . learning C . to be learned D . being learned √7. The police forbid ______ here. 正确答案：B 题目注释 A . park B . parking C . to park D . to be parked √8. My brother regretted _______ a lecture given by Professor Liu. 正确答案：A 题目注释 A . missing B . to miss C . missed D . being missed √9. We found many people________ in the meeting room. 正确答案：D 题目注释 A . seat B . seating C . to seat D . seated √10. My hometown is found __________. 正确答案：D 题目注释
一、单项选择题（共20道小题，共100.0分）1Her brother ______ to leave her in the dark room alone when she disobeyed his order. 1declared 1threatened 1warned 1exclaimed 知识点:Vocabulary 学生答案:[B;]标准答案:B 得分:[5]试题分值: 5.0提示:2It is certain that he will ______ his business to his son when he gets old.1take over 1think over 1hand over 1go over 知识点:Vocabulary 学生答案:[C;]标准答案:C 得分:[5]试题分值: 5.0提示:3The president spoke at the business meeting for nearly an hour without ______ his notes. 1bringing up 1referring to 1looking for 1trying on 知识点:Vocabulary 学生答案:[B;]标准答案:B 得分:[5]试题分值: 5.0 提示: 4 With oil prices keeping ______, people are hesitating whether to buy a car or not.1 rising 1 arising 1raising 、管路敷设技术通过管线敷设技术不仅可以解决吊顶层配置不规范高中资料试卷问题，而且可保障各类管路习题到位。在管路敷设过程中，要加强看护关于管路高中资料试卷连接管口处理高中资料试卷弯扁度固定盒位置保护层防腐跨接地线弯曲半径标高等，要求技术交底。管线敷设技术中包含线槽、管架等多项式，为解决高中语文电气课件中管壁薄、接口不严等问题，合理利用管线敷设技术。线缆敷设原则：在分线盒处，当不同电压回路交叉时，应采用金属隔板进行隔开处理；同一线槽内，强电回路须同时切断习题电源，线缆敷设完毕，要进行检查和检测处理。、电气课件中调试对全部高中资料试卷电气设备，在安装过程中以及安装结束后进行高中资料试卷调整试验；通电检查所有设备高中资料试卷相互作用与相互关系，根据生产工艺高中资料试卷要求，对电气设备进行空载与带负荷下高中资料试卷调控试验；对设备进行调整使其在正常工况下与过度工作下都可以正常工作；对于继电保护进行整核对定值，审核与校对图纸，编写复杂设备与装置高中资料试卷调试方案，编写重要设备高中资料试卷试验方案以及系统启动方案；对整套启动过程中高中资料试卷电气设备进行调试工作并且进行过关运行高中资料试卷技术指导。对于调试过程中高中资料试卷技术问题，作为调试人员，需要在事前掌握图纸资料、设备制造厂家出具高中资料试卷试验报告与相关技术资料，并且了解现场设备高中资料试卷布置情况与有关高中资料试卷电气系统接线等情况，然后根据规范与规程规定，制定设备调试高中资料试卷方案。、电气设备调试高中资料试卷技术电力保护装置调试技术，电力保护高中资料试卷配置技术是指机组在进行继电保护高中资料试卷总体配置时，需要在最大限度内来确保机组高中资料试卷安全，并且尽可能地缩小故障高中资料试卷破坏范围，或者对某些异常高中资料试卷工况进行自动处理，尤其要避免错误高中资料试卷保护装置动作，并且拒绝动作，来避免不必要高中资料试卷突然停机。因此，电力高中资料试卷保护装置调试技术，要求电力保护装置做到准确灵活。对于差动保护装置高中资料试卷调试技术是指发电机一变压器组在发生内部故障时，需要进行外部电源高中资料试卷切除从而采用高中资料试卷主要保护装置。
2011级数字信号处理实验报告 实验名称：实验一数字信号的产生和基本运算 1．实验要求 因为现实世界里存在的是模拟信号，因此数字信号处理的第一个问题是将信号离散化，得到一个数字信号，然后再进行数字处理。 (1) 常用数字信号序列的产生： 熟悉Matlab 产生数字信号的基本命令，加深对数字信号概念的理解，并能够用Matlab 产生和绘制出一些常用离散信号序列。请用Matlab 画出下列序列的波形（-10 北邮网络学院工商管理英语练习题答案1 一、阅读理解（共1道小题，共25.0分） Sixty-year-old grandmother, Fiona McFee, is going to stop working next year and she decided to realize a childhood dream and sail around the coast of Scotland in a small boat. Although the inside of the boat is very cosy, it has no running water or electricity. Fiona says she can live without these things but she plans to take her small CD player, her hot water bottle and a bag of books to make sure life isn’t too uncomfortable. We asked her if she was afraid of being at sea for so long. She said, “Well, I’m going to take a good compass (指南针). Anyway I’m not afraid of death because I love the sea---I just hope it loves me.” Fiona certainly has plenty of energy; in her spare time, she enjoys playing the piano, rock-climbing, canoeing and dancing. Although she is sixty, she doesn’t want to have a quiet and peaceful life. “I’m looking forward to having fun in the rest of my life and that’s exactly why I’d 数字信号处理期末复习题 一、填空题 1.数字频率ω与模拟角频率Ω之间的关系为 。 2.理想采样信号的频谱是原模拟信号的频率沿频率轴，每间隔 重复出现一次，并叠加形成的周期函数。 3.序列)(n x 的共轭对称部分)(n x e 对应着)(ωj e X 的 部分。 4.长度为N 的有限长序列)(n x 的M 点离散傅里叶变换的周期为 。 5.对实信号进行谱分析，要求谱分辨率Hz F 10≤，信号最高频率kHz f c 5.2=，则最小记录时间=min p T ，最少的采样点数=min N 。 6.在DIT-FFT 算法分解过程中，有16点的复数序列，可进行4级蝶形运算，则4级运算总的复数乘法次数为 。 7.如果序列)(n x 的长度为M ，则只有当频率采样点数N 满足 条件时，才可有频率采样)(k X 恢复原序列)(n x ，否则产生时域混叠现象。 8.设)(*n x 是)(n x 的复共轭序列，长度为N ，N n x DFT k X )]([)(=，则=N n x D F T )]([* 。 9.线性相位FIR 滤波器，若)1()(---=n N h n h ，N 为奇数的情况下，只能实现 滤波器。 10.给定序列()14j n x n e π??- ???=，试判断此序列是否为周期序列 ；若为周期序列，请给出此序列的最小正周期 ，若为非周期序列，请列写判别原 因 。（后面两个填空只需填一个）。 11.已知调幅信号的载波频率为1kHz ，调制信号频率100m f Hz =，则最小记录时间为 ，最低采样频率 。 12.系统差分方程为()()()21y n x n x n =++ ，其中()x n 和()y n 分别表示系统输入和输出，判断此系统（是，非）线性系统，（是，非）时不变系统，（是，非）因果系统，（是，不是）稳定系统。（划线部分是正确答案）。 13.周期信号()()0sin x n n ω= ，其中02π为有理数，其用欧拉公式展开后表达式为 ，其傅里叶变换为 。 14.序列()2n u n -的Z 变换表达式为 ，收敛域为 。 15.连续信号()a x t 是带限信号，最高截止频率为c f ，若采样角频率2s c f f < 会造成采样信号中的 现象。而序列()x n 的长度为M ，则只有当频域采样点数N M ≥时，才可由频域采样()X k 恢复原始序列，否则产生 现象。 16.对序列()()4x n R N =进行8点DFT （离散傅里叶变换）后，其幅度谱表达式为 ，相位谱表达式为 。 17.设()x n 是长度为N 的实偶对称序列，即()()x n x N n =-，则()X k 对称；如果()x n 是实奇对称序列，即()()x n x N n =--，则()X k 对称。 18.数字滤波器与模拟滤波器最大的区别为，频响函数()j H e ω是以 为周期的。对线性相位特性的滤波器，一般采用 数字滤波器设计实现。 19.已知FIR 滤波器的单位脉冲响应为：()h n 长度为6N =；()()05 1.5h h ==；北邮网络学院工商管理英语练习题答案1
数字信号处理期末复习题
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