分层法例题
例题二:(1)求节点不平衡弯矩(顺时针为正) AB 跨,(G 节点)
13.135.78.2121
12122-=??=ql
AB 跨,(H 节点) 13.135.78.2121
12122=??=ql
BC 跨,(H 节点)
32.76.58.212
1
12122-=??=ql BC 跨,(I 节点)
32.76.58.212
112122=??=ql
(2)求分配系数
667.09
.0421.4463.74
63.7=??+??=
GH u
333.068
.4516
.159.0421.4463.79.0421.4==??+???=GD u
353.052
.8652
.309.0421.4421.10463.7463.7==??+?+??=HG u
472.09
.0421.4421.10463.74
21.10=??+?+??=HI u
175.09
.0421.4421.10463.79
.0421.4=??+?+???=HE u
864.09
.0479.1421.104
21.10=??+??=IH u
136.0284.47444
.69.0479.1421.109.0479.1==??+???=IF u
(3)弯矩分配并传递(从弯矩比较大的节点开始,反向分配,满足精度要求小于1.0后结束)
先从G 、I 节点开始
76.8667.013.13=?- 乘0.5传递系数,传递到H 节点,得4.38 32.6864.032.7-=?-
乘0.5传递系数,传递到H 节点,得-3.16
H 点不平衡弯矩为03.716.332.738.413.13=--+分配 左梁
48.2353.003.7-=?乘
0.5传递系数,传递到G 节点,得-1.24
右梁32.3472.003.7-=?乘0.5传递系数,传递到I 节点,得-1.66 下柱23.1175.003.7-=?
G 点不平衡弯矩分配83.0667.024.1=?- 传递到G 节点,得0.42 I 点平衡弯矩分配43.1864.066.1=?- 传递到G 节点,得0.72 H 点不平衡弯矩为14.172.042.0=+分配