c语言08考题2

例如：fun1(0.76)=2.175

fun1(3.00)=5.307

fun1(3.76)=9.111

2、打开程序cprog012.c，完成其中的函数fun2(int a[],int n,int b[],int c[])，实现：

1）将数组a中大于-20的元素，依次存放到数组b中；

2）将数组b的元素按照从小到大的顺序存放到数组c中；

3）函数返回数组b中的元素个数。

Cprog011.c

#include

#include

double fun1(double x)

{ /**/

x=(1+sin(x)+exp(x))/(1+x);

return(x);

/**/

}

void main()

{

clrscr();

printf("fun1(0.76) = %8.3lf\n", fun1(0.76)); printf("fun1(3.00) = %8.3lf\n", fun1(3.00)); printf("fun1(3.76) = %8.3lf\n", fun1(3.76)); }

Cprog012.c

#include

#include

#include

#include

int fun2(int a[],int n,int b[],int c[])

{ /**/

int i,k,temp,j=0;

for (i=0;i

if (a[i]>-20) b[j++]=a[i];

for (i=0;i

for (i=0;i

for (k=i+1;k

if (c[i]>c[k])

{ temp=c[i];

c[i]=c[k];

c[k]=temp;

}

return j;

/**/

}

void main()

{ int n = 10, i, nb;

int aa[10] = {12, -10, -31, -18, -15, 50, 17, 15, -20, 20}; int bb[10], cc[10];

clrscr();

printf("There are %2d elements in aa.\n", n);

printf("They are: ");

for(i=0; i

printf("\n");

nb = fun2(aa, n, bb, cc);

printf("Elements in bb are: ");

for (i=0; i

printf("\n");

printf("Elements in cc are: ");

for(i=0; i

printf("\n");

printf("There are %2d elements in bb.\n", nb);

}

如fun1(0.76)=3.582

fun1(3.00)=5.369

fun1(3.76)=8.931

2、打开程序Cprog022.c，完成其中的函数fun2(char a[] ,char b[] ,char c[] )，实现：将三个字符串a、b、c从小到大排

序后输出。

注意：字符串比较函数为strcmp(str1,str2)，

字符串赋值函数为strcpy(str1,str2)。

Cprog021.c

#include

#include

double fun1(double x)

{ /**/

x=(exp(x)+fabs(x-6))/(x+1.3);

return x;

/**/

}

void main()

{

clrscr();

printf("fun1(0.76) = %8.3lf\n", fun1(0.76)); printf("fun1(3.00) = %8.3lf\n", fun1(3.00)); printf("fun1(3.76) = %8.3lf\n", fun1(3.76)); }

Cprog022.c

#include

#include

#include

#include

void fun2(char a[],char b[],char c[])

{

/**/

char temp[15];

if (strcmp(a,b)>0)

{

strcpy(temp,a);

strcpy(a,b);

strcpy(b,temp);

}

if (strcmp(a,c)>0)

{

strcpy(temp,a);

strcpy(a,c);

strcpy(c,temp);

}

if (strcmp(b,c)>0)

{

strcpy(temp,b);

strcpy(b,c);

strcpy(c,temp);

}

/**/

}

void main()

{ char str1[15]="Fuzhou",str2[15]="Fujian",str3[15]="China"; clrscr();

fun2(str1,str2,str3);

printf("The ordered strings is : %s, %s, %s\n",str1,str2,str3); getch();

}