安徽省舒城中学2020-2021学年高一上学期开学考试英语试题

安徽省六安市舒城县2021-2022学年高一英语上学期第一次月考试题分值：150分时长：120分钟注意事项：1. 答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。

2. 回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

回答非选择题时，将答案写在答题卡上，写在本试卷上无效。

3. 考试结束后，将本试卷和答题卡一并交回。

第一部分听力（共两节，满分30分）做题时，先将答案标在试卷上。

录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例：How much is the shirt?A. £19. 15.B. £9. 18.C. £9. 15.答案是 C。

1. What is the man doing?A. Asking the way.B. Giving directions.C. Correcting a mistake.2. What dress size does the woman want?A. 8.B. 10.C. 12.3. What is the woman likely to do?A. Make a phone call.B. Handle the problem.C. Have a rest.4. Which tour does the man seem to be interested in?A. The evening tour.B. The half-day tour.C. The full-day tour.5. Where are the speakers?A. At a canteen.B. At a clinic.C. At a bank.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。

舒城中学2021—2021学年度第一学期第四次统考高一英语第一局部听力〔共两节，总分值30分〕第一节〔共5小题；每题1.5分，总分值7.5分〕听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项当选出最正确选项。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What is the man going to do on Sunday?A.Visit his mother.B. Do some gardeningC. Move into a new house.2. What does the man think of the building might be?A. An apartment building.B. A hotel.C. A department store.3. Where does the conversation take place?A. In a store.B. In a bank.C. In a classroom.4. When will the next bus come?A. At 6:35.B. At 6:45.C. At 7:00.5. When does the conversation probably take place?A. At 4:30 p.mB. At 5: 00 p.m.C. At 5:30 p.m.第二节〔共15小题；每题1.5分，总分值22.5分〕听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项当选出最正确选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每题5秒钟；听完后，各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料，回答第六、7题。

6. What’s the probable relationship between the speakers?A. FriendsB. Neighbors.C. Customer and waitress.7. How will Bill and Mary go home?A. By busB. By taxiC. By subway.听第7段材料，回答第八、9题。

安徽省六安市舒城中学2020-2021学年高一英语上学期第四次月考（12月）试题时间：120分钟分值：150分第一部分听力(共两节，满分30分)第一节(共5小题；每小题1.5分，满分7.5分)听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. How many sets of materials will the woman print?A．32. B.37 C.272.Where does the conversation probably take place?A.In a gardenB.In a palaceC.In a restaurant3. What did the woman do last night?A.She stayed with her cousinB.She went to a cinemaC.She visited her friend4. What is the weather like now?A.CloudyB.SunnyC.Rainy5. What advice does the woman give to man?A.Washing his clothes by handB.Buying a new washing machineC.Washing fewer clothes at a time第二节(共15小题：每小题1.5分，满分22.5分)听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听下面一段对话，回答第6和第7两个小题。

安徽省舒城县2020—2021学年高一英语上学期研究性学习材料试题（三）（无答案）第一部分阅读明白得（共20小题；每小题2分，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项中选出最佳选项AOur planet was born some billions of years ago. Ever since this planet has developed, it has surprised us human beings. No matter how much we human beings have developed technological ly, we cannot ever create this kind of natural planet. The human race can only discover some amazing facts about it. Let us find out what some of themare.On September 13, 1922 El Azizia, a place in Libya, recorded a temperature of 136 degrees Fahrenheit. This was the highest temperature ever measured (测量) on the planet Earth. The highest waterfall in the world is Angel Falls in Venezuela, which drops from an amazing height of 3,212 feet. The waterfall drops over the edge of Auyantepui in the Canaima National Park. The gravitational pull (万有引力) of the Earth can be escaped if someone moves at a speed of 6.95 miles per second. At such a speed, one could travel from New York to Philadelphia in just 20 seconds. If the entire water in the world’s oceans evaporated, the salt we got from these oceans could cover the entire planet with a 500-foot deep layer of salt. The deepest lake on Earth is Lake Baikal in Russia. Lake Baikal is the largest freshwater lake in t he world, containing about 20% of the world’s unfrozen surface fresh water. The Andes in South America spreads over 4,525 miles. This is the longest mountain range (山脉) in the world.Did you know that the biggest valley in the world is the Grand Valley in Mesa County, Colorado and Grand County, Utah? It is about 30 miles (48 km) long and 5 miles (8 km) wide, along the Colorado River. The amazing facts about the earth are too many to be told completely above.1. The underlined word “evaporated” in Paragraph 2 most probably means“_____”.A. became salt graduallyB. became clear slowlyC. changed into warmer waterD. changed into gas or disappeared2. Where is the longest mountain range in the world?A. In Russia.B. In Libya.C. In South America.D. At the Oregon-Idaho border.3.We can learn from this passage that _____.A. Lake Baikal is the biggest lake in the worldB. the highest temperature ever measured was 136 ℃C. the Angel Falls drops from a height of 3,212 metersD. one end of the Grand Valley is in Colorado and the other in UtahBThis is an open letter to the three people who stole my handbag from the department store where I am employed as a shop assistant.When you took my bag, I don't know what you thought you were going to get. With my wages, there's not much left on a Tuesday. I hope the ￡5 was useful to you .I have informed the social security office so you won't be able to cash the child benefit next week. I hope that won't leave you too short. But if you really need a couple of pounds, I suppose you could always cash one of the two checks left in my check book. Of course,I phoned the bank right away and the check-casing card is no longer valid, so it won’t be much use to you.Actually I don't mind about the money too much. We single parents who work to support our families understand only too well what it means to be short of cash. However, I don’t suppose it went very far among the three of you. Sorry about that!I wish you had left the bag behind and just taken the wallet and check book. There were all kinds of papers in it, and notes and things that I really need. I really think that was very inconsiderate of you. I mean, how would you like something like that to happen to you?Well, perhaps the bag will turn up. It wasn't even an expensive one, just a plain, old brown leather shoulder bag. You probably dumped it in the nearest rubbish bin or threw it into the bushes. We've looked around, of course, but no one saw which way you went after you left the shop.I'm not really angry with you. I know how the pressures of modern living can affect us, but I am sad at the loss of my personal things. I feel violated and helpless. The police were very icy, and they just shruggedtheir shoulders. "It happens all the time," they told me. Some small comfort, I suppose. But I've lost just a little more faith in human nature. And as my young son said when I told him what had happened, "Why? Mummy, why us?" I couldn't answer that question. I wonder if you can.4.In writing Paragraph 2, the writer wants to ．A. describe the contents of the bag in detail．B. give some suggestions to the three thievesC. tell the thieves hardly any money was availableD. state the fact that she was careless with the money5.Which of the following is the most valuable to the writer?A. The cash in her bagB. The papers and notes in the bagC. The handbag itselfD. The check books in the bag6.What can we conclude about the police?舒中高一英语第2页(共8页)A. They have doubts about human natureB. They show sympathy for the womanC. They think the case quite commonD. They are unable to find the thieves7.Why does the author write the letter?A. To give the thieves a serious warningB. To complain about the fall of moralityC. To call people’s attention to their belongingsD. To express her affection for her valuable bagCParents and kids today dress alike, listen to the same music, and are friends. Is this a good thing? Sometimes, when Mr. Ballmer and his 16-year-old daughter, Elizabeth, listen to rock music together and talk about interests they both enjoy, such as pop culture, he remembers his more distant relationship with his parents when he was a teenager.“I would never have said to my mom, ‘Hey, the new Weezer album is really great. How do you like it?’” says Ballmer. “There was just a complete gap in taste.”Music was not the only gulf. From clothing and hairstyles to activities and expectations, earlier generations of parents and children often appeared to move in separate orbits(轨道).Today, the generation gap has not disappeared, but it is getting narrow in many families. And parent—child activities, from shopping to sports, involve a feeling of trust and friendship that can continue into adulthood.But family experts warn that the new equality can also result in less respect for parents. “There’s still a lot of strictness and authority(权威) on the part of parents out there, but there is a change happening,” says Kerrie, a psychology professor at Lebanon Valley College. “In the middle of that change, there is a lot of confusion among parents.”Family researchers offer a variety of reasons for these changing roles and attitudes. They see the 1960s as a turning point. Great cultural changes led to more open communication and a more democratic(民主的) process that encourages everyone to have a say.“My parents were on the ‘before’ side of that change, but today’s parents, the 40-year-olds, were on the ‘after’ side,” explains Mr. Ballmer. “It’s notsomething easily achieved by parents these days, because life is more difficult to understand or deal with, but sharing interests does make it more fun to be a parent now.”8. The underlined word “gulf” in Para.3 most pro bably means _________.A. distanceB.interest C. similarity D. cooperation9. The change in today’s parent-child relationship is _________.A. more confusion among children.B. less respect for parents from children.C. new equality between parents and children.D. more strictness and authority on the part of parents.10. By saying “today’s parents, the 40-year-olds, were on the ‘after’ side.”the author means that today’s parents _________.A. can set a limit to the change.B. follow the trend of the change.C. fail to take the change seriously.D. have little difficulty adjusting(适应)to the change.11. The purpose of the passage is to _________.A. describe the difficulties today’s parents have met with.B. discuss the development of the parent—child relationship.C. suggest the ways to handle the parent—child relationship.D. compare today’s parent—child relationship with that in the past.DLONDON: What could possibly be wrong with planting trees? The benefits are obvious; they firm the soil, soak up (摄取) extra water and take carbon dioxide (二氧化碳) our of the atmosphere.However, it now turns out that planting trees could add to global warming.Tree roots do a great job of keeping soil firmly on the ground and out of the wind’s power. The problem is that some of those dust clouds play an important part in soaking up carbon dioxide.Huge dust storms blow out over the oceans from dry parts of North Africa and central Asia. Tons of dust are lifted and left as a thin film over the ocean surface. The dust fuels oceanic life.Dust from China is carried east and left in the Pacific Ocean. If a tree-planting program there is successful and the dust supply reduced, the net result may be that less carbon dioxide gets locked away in the ocean.Andy Ridgwell, an environmental scientist from the University of East Anglia,has spent the past few years studying dust and says his work “shows clearly the complexity of the system and the importance of not tinkering(粗劣地修补) with it without understanding the results. For this reason the need is to focus(集中) on cutting carbon dioxide giving off rather than monkeying (瞎弄) about with the land surface.”An American scientist, Robert Jackson, has shown that when native grassland areas are invaded(侵入) by trees, carbon is lost from the soil. “We are studying why the soil carbon disappears, but one theory is that trees do a lot more of their growing above ground compared to grasses, so less carbon goes directly into the soil from trees, ” says Jackson.舒中高一英语第4页(共8页)In wet areas of the world, the gain from trees absorbing carbon dioxide above ground seems to be outweighed(超过) by the loss of carbon from the soil below ground. Countries that plan to combatglobal warming by planting trees may have to think again.Solutions to environmental problems are often more complex than they first appear, and understanding the Earth’s climate is a very great challenge.12．People usually hold the opinion that .A．huge dust storms can destroy carbon dioxideB．huge dust storms can destroy the oceans on the earthC．huge dust storms can’t do anything beneficial for manD．planting trees is the only way to control huge dust storms 13．Andy Ridgwell, the environmental scientist, believes that .A．dust plays a more important part than treesB．trees shouldn’t have been planted in dry placesC．carbon dioxide is harmful to everything on the earthD．environmental problems are more complex than expected 14．Robert Ja ckson’s experiment proves that.A．grassland areas should be covered by forestsB．trees hold more carbon than grassesC．carbon can turn grass into dustD．less carbon can make trees grow faster15．The underlined word “combat” in the last paragraph means.A．learn about B．fightagainst C．live with D．give up第二节（共五小题，每小题2分，共10分）依照短文内容，从短文后的选项中选出能填入空白处的最佳选项。

3.2.1 单调性与最大（小）值（精练）【题组一 定义法判断或证明函数的单调性】1．（2020·上海高一专题练习）证明幂函数12()f x x =在[)0,+∞上是增函数 【答案】证明见解析 【解析】设120x x ≤<， 则11221212()()f x f x x x-=-121212x x x x x x -=-=+12x x <120x x ∴-<120x x ∴+>12()()0f x f x ∴-<即12()()f x f x <，此函数在[0,)+∞上是增函数.2．（2021·全国高一课时练习）已知函数f (x )=12x x ++，证明函数在(-2，+∞)上单调递增. 【答案】证明见解析.【解析】证明：∀x 1，x 2∈(-2，+∞)，且x 1>x 2>-2，f (x )=11122x x x +=-++ 则f (x 1)-f (x 2)=212x -+112x +=1212-(2)(2)x x x x ++， 因为x 1>x 2>-2，所以x 1-x 2>0，x 1+2>0，x 2+2>0，所以1212-(2)(2)x x x x ++>0，所以f (x 1)>f (x 2)，所以f (x )在(-2，+∞)上单调递增.3．（2021·福建三明市·三明一中高一开学考试）已知函数()12x f x x -=+，[]3,5x ∈. （1）判断函数()f x 的单调性，并证明； （2）求函数()f x 的值域.【答案】（1）单调递增，证明见解析；（2）24,57⎡⎤⎢⎥⎣⎦【解析】（1）()12331222x x f x x x x -+-===-+++在区间[]3,5上单调递增，证明如下：任取[]12,3,5x x ∈且12x x <，()()1212213333112222f x f x x x x x ⎛⎫⎛⎫-=---=- ⎪ ⎪++++⎝⎭⎝⎭ ()()()()()()()12121212323232222x x x x x x x x +-+-==++++，因为1235x x ≤<≤，所以120x x -<，120x +>，220x +>， 所以()()120f x f x -<，即()()12f x f x <， 所以函数()f x 在区间[]3,5上单调递增.（2）由（1）知：()f x 在区间[]3,5上单调递增， 所以()()min 3123325f x f -===+，()()max 5145527f x f -===+， 所以函数()f x 的值域是24,57⎡⎤⎢⎥⎣⎦. 4．（2021·六安市裕安区新安中学高一期末）设函数1()f x x x=+，(1,)x ∈+∞.判断函数()f x 的单调性，并用定义证明；【答案】在(1,)+∞上为增函数，证明见解析. 【解析】任取12,(1,)x x ∈+∞且12x x <，()()12121211f x f x x x x x -=+-- ()()()()1212211212121212111x x x x x x x x x x x x x x x x --⎛⎫⎛⎫-=-+-=-+= ⎪ ⎪⎝⎭⎝⎭，因为121x x <<，所以120x x -<，1210x x ->， 所以()()120f x f x -<，所以()()12f x f x <，所以()f x 在(1,)+∞上为增函数； 【题组二 性质法判断函数的单调性】1．（2020·巩义市第四高级中学高一月考）函数()2f x x=的单调递减区间为（ ） A ．(),-∞+∞ B ．()(),00,-∞⋃+∞ C ．()(),0,0,-∞+∞ D ．()0,∞+【答案】C 【解析】()2f x x=的定义域为()(),00,-∞⋃+∞， 图象如图所示：所以()2f x x=的单调递减区间为()(),0,0,-∞+∞， 故选：C2（2020·台州市黄岩中学高一月考）函数f (x )＝1－11x -（ ） A ．在(－1，＋∞)上单调递增 B ．在(1，＋∞)上单调递增 C ．在(－1，＋∞)上单调递减 D ．在(1，＋∞)上单调递减 【答案】B【解析】f (x )图象可由y ＝－1x图象沿x 轴向右平移一个单位长度，再向上平移一个单位长度得到，如图所示．故选：B3．（2021·吉林长春市·长春外国语学校高一开学考试）以下函数在其定义域上为增函数的是（ ） A ．1(0)x yx xB ．2(0)y x x xC ．1y x =-D ．2yx【答案】B【解析】对于A 选项，111(0)x yx xx，由于反比例函数()10y x x=>为减函数，故1(0)x yx x为减函数，A 选项错误； 对于B 选项，2(0)y x x x的对称轴为102x =-<，开口向上，故2(0)y x x x 为增函数，B选项正确；对于C 选项，由于()11y x x =-≤上是减函数，故由复合函数的单调性得1y x =-为定义域(],1-∞上的减函数，C 选项错误； 对于D 选项，2y x 为减函数，故D 选项错误.故选：B.4．（2021·深圳市皇御苑学校高一期末）函数23y x x =+的单调递减区间为A ．3,2⎛⎤-∞- ⎥⎝⎦B ．3,2⎡⎫-+∞⎪⎢⎣⎭C ．[)0,+∞D ．(],3-∞-【答案】D【解析】由题意，230x x +≥，可得3x ≤-或0x ≥， 函数23y x x =+的定义域为(][),30,-∞-⋃+∞，令23t x x =+，则外层函数y t =在[)0,+∞上单调递增，内层函数23t x x =+在上(],3-∞-单调递减，在[)0,+∞上单调递增， 所以，函数23y x x =+的单调递减区间为(],3-∞-.故选：D.5．（2021·全国高一课时练习）下列函数中，在区间(1，+∞)上单调递增的是（ ） A ．y =-3x -1 B ．y =2xC ．y =x 2-4x +5 D ．y =|x -1|+2【答案】D【解析】由一次函数的性质可知，y =-3x -1在区间(1，+∞)上单调递减，故A 错误； 由反比例函数的性质可知，y =2x在区间(1，+∞)上单调递减，故B 错误， 由二次函数的性质可知，y =x 2-4x +5在(-∞，2)上单调递减，在(2，+∞)上单调递增，故C 错误； 由一次函数的性质及图象的变换可知，y =|x -1|+2在(1，+∞)上单调递增. 故选：D.6．（2021·浙江高一期末）函数()254f x x x =-+的单调递减区间为________【答案】(],1-∞（或(),1-∞）【解析】对于函数()f x ，有2540x x -+≥，解得1x ≤或4x ≥. 所以，函数()f x 的定义域为(][),14,-∞+∞.内层函数254u x x =-+在区间(],1-∞上为减函数，在区间[)4,+∞上为增函数， 外层函数y u =在[)0,+∞上为增函数，因此，函数()254f x x x =-+的单调递减区间为(],1-∞（或(),1-∞）.故答案为：(],1-∞（或(),1-∞）.7．（2021·贵溪市实验中学高二期末）函数2()26f x x x =+-的单调递增区间是____________；【答案】[)1,-+∞【解析】函数()226f x x x =+-的对称轴为1x =-，开口向上，所以函数()f x 的单调增区间为[)1,-+∞. 故答案为：[)1,-+∞8．（2020·和平区·天津市第二南开中学高一期中）函数243y x x =-++，[]0,3x ∈的单调递增区间是_____．【答案】[]0,2【解析】243y x x =-++的图象开口向下，又243y x x =-++的对称轴为42(1)2x =-=-⨯，()f x ∴的单调递增区间是[]0,2.故答案为：[]0,2.【题组三 图像法判断函数的单调性】1．（2020·江苏）函数()||1f x x =-与()()2g x x x =-的单调递增区间分别为（ ） A ．[1，+∞)，[1，+∞) B ．(﹣∞，1]，[1，+∞) C ．(1，+∞)，(﹣∞，1] D ．(﹣∞，+∞)，[1，+∞)【答案】A 【解析】()1,111,1x x f x x x x -≥⎧=-=⎨-+<⎩，()f x ∴在[)1,+∞上单调递增，()()222()211g x x x x x x -=-==--，()g x ∴在[)1,+∞上单调递增，故选：A.2．（2020·太原市·山西实验中学高一月考）函数()2f x x x =-的单调减区间是（ ） A ．[]1,2 B ．[]1,0-C ．[]0,2D ．[2,)+∞【答案】A 【解析】()(2),2,(2),2,x x x f x x x x -⋅≥⎧=⎨-⋅<⎩∴直接通过解析式，结合二次函数图象得：(,1),(2,)-∞+∞递增，在[]1,2递减，故选：A.3．（2021·河南郑州市）函数f （x ）=|x 2﹣6x+8|的单调递增区间为（ ） A ．[3，+∞） B ．（﹣∞，2），（4，+∞） C ．（2，3），（4，+∞） D ．（﹣∞，2]，[3，4]【答案】C【解析】画出2()68f x x x =-+的图象如图：由图象可知，函数的增区间为(2,3),(4,+∞），故选C.4．（2020·福建省南安市侨光中学高一月考）函数()11g x x x =⋅-+的单调减区间为（ ） A ．12⎛⎤-∞ ⎥⎝⎦， B ．112⎡⎤⎢⎥⎣⎦，C ．[)1+∞， D ．][112⎛⎫-∞+∞ ⎪⎝⎭，，【答案】B【解析】()221,111=1,1x x x g x x x x x x ⎧-+≥=⋅-+⎨-++<⎩，画出函数图象，如图所示：根据图象知：函数的单调减区间为112⎡⎤⎢⎥⎣⎦，. 故选：B.5．（2021·银川市）函数2()68f x x x =-+的单调递增区间为（ ） A ．[3,)-+∞ B ．(,2),(4,)-∞+∞ C ．(2,3),(4,)+∞D ．(,2],[3,4]-∞-【答案】C【解析】2226824()686824x x x x f x x x x x x ⎧-+≤≥=-+=⎨-+-<<⎩或，所以()f x 递增区间是(2,3),(4,)+∞. 故选:C.6．（2021·重庆北碚区）函数()|2|f x x x =-的增区间是 A ．(,1]-∞ B ．[2,)+∞C ．(,1],[2,)-∞+∞D ．(,2)-∞【答案】C【解析】222,2()22,2x x x f x x x x x x ⎧-≥=-=⎨-+<⎩由二次函数的图象可知()f x 在(,1],[2,)-∞+∞上是增函数故选：C7．（2021·黑龙江哈尔滨市）已知函数()||2f x x x x =-，则有（ ） A ．()f x 是偶函数，递增区间为[0，)+∞ B ．()f x 是偶函数，递增区间为(-∞，1] C ．()f x 是奇函数，递减区间为[1-，1] D ．()f x 是奇函数，递增区间为(-∞，0] 【答案】C【解析】因为()||2f x x x x =-，所以()22()f x x x x x x x f x -=--+=-+=-，故()f x 为奇函数，因为222,0()2,0x x x f x x x x ⎧-=⎨--<⎩，结合二次函数性质可知，()f x 的单调递减区间为[1-，1]．故选：C ．8．（2020·龙岩市高级中学高一期中）（多选）函数2()68f x x x =-+在下列区间（ ）上单调递减． A ．(,2)-∞ B ．(,3)-∞C ．[]3,4D ．()2,3【答案】AC【解析】解：因为222268,4()6868,2468,2x x x f x x x x x x x x x ⎧-+≥⎪=-+=-+-<<⎨⎪-+≤⎩，函数图象如下所示：由图可知函数的单调递增区间为()2,3和()4,+∞，单调递减区间为(),2-∞和()3,4 故选：AC9．（2021·江苏扬州市）函数()|2|3f x x x =--的单调递增区间为______ 【答案】()(,1),2,-∞+∞【解析】由题意2x ≥时，22()(2)323(1)4f x x x x x x =--=--=--，在[2,)+∞是是增函数，2x <时，22()(2)323(1)2f x x x x x x =--=-+-=---，在(,1)-∞是递增，在(1,2)上递减．∴增区间为(,1)-∞，(2,)+∞． 故答案为：(,1)-∞，(2,)+∞．10．（2021·江苏南京市）函数()21f x x =-的单调增区间为______.【答案】（-1，0）和（1，+ ∞） 【解析】()21f x x =-可画出函数图象如下所示：由函数图象可知，函数在()1,0-和()1,+∞上单调递增. 故答案为：()1,0-和()1,+∞ 【题组四 已知单调性求参数】1．（2021·新疆阿勒泰地区·高一期末）若函数f (x )＝(2a －1)x ＋b 在R 上是单调减函数，则有（ ）A ．a ≥12 B ．a ≤12 C ．a >12D ．a <12【答案】D【解析】函数f (x )＝(2a －1)x ＋b 在R 上是单调减函数，则2a －1<0，即a <12. 故选：D.2．（2021·全国）若函数()|2|f x x a =+的单调递减区间是(,3]-∞，则a 的值为 A ．3- B ．3C ．6-D ．6【答案】C 【解析】当2a x ≤-时，()2f x a x =-，()f x ∴单调递减区间为,2a ⎛⎤-∞- ⎥⎝⎦，32a∴-=，解得：6a =-.故选：C . 3．（2021·广西桂林市·高一期末）如果函数2()2(1)2f x x a x =--+在[3,)+∞上是增函数，那么实数a 的取值范围（ ） A ．3a ≤-B ．2a -C ．5a ≤D ．5a ≥【答案】B【解析】函数2()2(1)2f x x a x =--+为二次函数，对称轴为1x a =-，故函数在(),1a -∞-单调递减，(1+)a -∞，单调递增，因此：132a a -≤∴≥-.故选：B4．（2021·江西宜春市·高安中学高一期末（理））已知函数f (x )=221,143,1x x x x x ⎧-+<⎨-+≥⎩，在(0,3)a -上单调递减，则实数a 的取值范围是（ ） A ．[3，4] B ．[3，5]C ．(3，4]D ．(]3,5【答案】D【解析】函数221,1()43,1x x f x x x x ⎧-+<=⎨-+≥⎩，画出函数()f x 的大致图象，如图所示：函数()f x 在(0,3)a -上单调递减，∴由图象可知：032a <-≤，解得：35a <≤，故实数a 的取值范围是：(]3,5. 故选：D.5．（2021·四川省遂宁市第二中学校高一月考（文））已知函数()2f x ax =-在[0,2]上单调递减，则a的取值范围是（ ） A ．(0,1] B ．(0,1)C ．(0,2]D ．[2,)+∞【答案】A【解析】因为函数()2f x ax =-在[0,2]上单调递减，所以0220a a >⎧⎨-≥⎩ ，解得01a <≤，所以a 的取值范围是(0,1]， 故选： A6．（2021·北京门头沟区·大峪中学高一期中）已知函数()2f x ax x =-,若对任意[)12,2,x x ∈+∞,且12x x ≠,不等式()()12120f x f x x x ->-恒成立,则实数a 的取值范围是A ．1,2⎛⎫+∞⎪⎝⎭B ．1,2⎡⎫+∞⎪⎢⎣⎭C ．1,4⎛⎫+∞⎪⎝⎭D ．1,4⎡⎫+∞⎪⎢⎣⎭【答案】D【解析】不妨设x 2＞x 1≥2，不等式()()1212f x f x x x --=22112212ax x ax x x x --+-=()()()12121212a x x x x x x x x -+---=a （x 1+x 2）﹣1，∵对任意x 1，x 2∈[2，+∞），且x 1≠x 2，不等式()()1212f x f x x x --＞0恒成立，∴x 2＞x 1≥2时，a （x 1+x 2）﹣1＞0，即a ＞121x x +恒成立∵x 2＞x 1≥2 ∴121x x +＜14∴a ≥14，即a 的取值范围为[14，+∞）； 故选：D ．7．（2021·云南大理白族自治州·宾川四中高一开学考试）若()()31121a x a x f x ax x ⎧-+<=⎨-≥⎩，，是定义在(),-∞+∞上的减函数，则a 的取值范围是（ ） A ．11,63⎡⎫⎪⎢⎣⎭B ．11,63⎛⎤⎥⎝⎦C ．10,3⎛⎫ ⎪⎝⎭D ．1,3⎛⎤-∞ ⎥⎝⎦【答案】A【解析】因为()()31121a x a x f x ax x ⎧-+<=⎨-≥⎩，，是定义在(),-∞+∞上的减函数，所以(31)1231020a a aaa-⨯+≥-⎧⎪-<⎨⎪-<⎩，即1613aaa⎧≥⎪⎪⎪<⎨⎪>⎪⎪⎩，解得1163a≤<，故选：A8．（2021·应城市第一高级中学高一期末）（多选）函数()21x af xx-=+在区间()b+∞，上单调递增，则下列说法正确的是（）A．2a>-B．1b>-C．1b≥-D．2a<-【答案】AC【解析】()22211x a af xx x-+==-++，()f x在区间()b+∞，上单调递增，20a∴+>，2a>-∴，由()f x在区间()1+∞-，上单调递增，1b.故选：AC9．（2021·江苏高一）（多选）已知函数()25,1,1x ax xf x axx⎧---≤⎪=⎨>⎪⎩是R上的增函数，则实数a的取值可以是（）A．0B．2-C．1-D．3-【答案】BD【解析】由题意，函数25y x ax=---的图象开口朝下，对称轴为2ax=-，因为函数()25,1,1x ax xf x axx⎧---≤⎪=⎨>⎪⎩是R上的增函数，所以1215aaa a⎧-≥⎪⎪⎨<⎪⎪---≤⎩，解得32a--≤≤.所以实数a 的取值可以是2-，3-. 故选：BD.10.（2021·浙江高一期末）已知函数()()()()()24312121xa x f x x a x x ⎧-≤⎪=⎨+-+>⎪⎩在R 上是增函数，则实数a 的取值范围是_______． 【答案】[)1,1-【解析】要使()f x 在R 上是增函数，则431114352a a a a ->⎧⎪-≤⎨⎪-≤-⎩，解得11a -≤<.故答案为：[)1,1-.11．（2021·青海西宁市·高一期末）函数2()21f x x kx k =-++在区间[1,3]-上不单调．．．，则实数k 的取值范围是_________． 【答案】()4,12-【解析】二次函数2()21f x x kx k =-++在区间[1,3]-上不单调．．．则对称轴()1,34kx =∈-，即()4,12k ∈- 故答案为：()4,12-12．（2021·湖南高一期中）已知函数()()22212f x x k x k =+-++．（1）若不等式()0f x <的解集为{}3|1x x <<，求实数k 的值； （2）若函数()f x 在区间[]2,4上不单调，求实数k 的取值范围． 【答案】（1）1k =-；（2）()3,1--.【解析】（1）由已知得方程()222120x k x k +-++=的两根为1和3，故由()()2241420k k ∆=--+>，解得12k <-， 再由韦达定理有()22113213k k ⎧--=+⎨+=⨯⎩，得112k =-<-，符合要求， 故实数k 的值为1k =-；（2）∵函数()f x 在区间[]2,4上不单调，二次函数对称轴为()1x k =--， ∴()214k <--<，解得31k -<<-， 所以实数k 的取值范围为()3,1--．13．（2021·浙江高一期末）已知函数2()2(1)4f x x k x =+-+． （Ⅰ）若函数()f x 在区间[2,4]上具有单调性，求实数k 的取值范围； （Ⅱ）若()0f x >对任意的[1,2]x ∈恒成立，求实数k 的取值范围． 【答案】（1）(,3][1,)-∞-⋃-+∞（2）()1,-+∞ 【解析】（1）由函数2()2(1)4f x x k x =+-+知， 函数()f x 图象的对称轴为1x k =-. 因为函数()f x 在区间[]2,4上具有单调性， 所以12k -≤或14k -≥， 解得3k ≤-或1k ≥-，所以实数k 的取值范围为(,3][1,)-∞-⋃-+∞. （2） 因为()0f x >对任意的[1,2]x ∈恒成立， 所以可得42(1)k x x->--对任意的[1,2]x ∈恒成立， 因为444()244y x x x x x=--=-+≤-⋅=-，当且仅当2x =时等号成立， 即max 4y =-，所以只需2(1)4k ->-， 解得1k -<，所以实数k 的取值范围为()1,-+∞. 【题组五 利用单调性解不等】1．（2021·全国高一课时练习）已知y =f (x )是定义在区间(-2，2)上单调递减的函数，若f (m -1)>f (1-2m )，则m 的取值范围是_______.【答案】1223⎛⎫- ⎪⎝⎭，【解析】由题意得：-2-12-21-22-11-2m m m m <<⎧⎪<<⎨⎪<⎩，，，解得12-<m <23.故答案为：1223⎛⎫- ⎪⎝⎭，2（2021·全国高一课时练习）函数()y f x =满足：对任意的12,x x R ∈总有1212()()0f x f x x x ->-．则不等式2(1)(2)f m f m +>的解集为________．【答案】{|1}m m ≠【解析】因为对任意的12,x x R ∈总有1212()()0f x f x x x ->-所以函数()y f x =是R 上的单调增函数，从而由2(1)(2)f m f m +>得212m m +>，解得1m ≠． 故答案为：{|1}m m ≠3．（2021·全国高一课时练习）已知f (x )是定义在(,0]-∞上的单调递增函数，且(2)3f -=，则满足(23)3f x -<的x 的取值范围是_______.【答案】x ＜12【解析】因为(2)3f -=，所以(23)3f x -<和化为(23)(2)f x f -<-， 又因为f (x )是定义在(,0]-∞上的单调递增函数，所以232x -<-，解得12x <. 故答案为：12x <. 4（2021·江苏南通市·高一开学考试）设函数()f x 是定义在(),-∞+∞上的增函数，实数a 使得()()212f ax x f a --<-对于任意[]0,1x ∈都成立，则实数a 的取值范围是（ ）A ．(,1)-∞B ．[]2,0-C ．()222,222---+ D ．[]0,1【答案】A【解析】解：法一：由条件得1﹣ax ﹣x 2＜2﹣a 对于x ∈[0，1]恒成立 令g （x ）＝x 2+ax ﹣a +1，只需g （x ）在[0，1]上的最小值大于0即可．g （x ）＝x 2+ax ﹣a +1＝（x 2a +）224a --a +1．①当2a-＜0，即a ＞0时，g （x ）min ＝g （0）＝1﹣a ＞0，∴a ＜1，故0＜a ＜1；②当02a ≤-≤1，即﹣2≤a ≤0时，g （x ）min ＝g （2a -）24a =--a +1＞0，∴﹣2﹣22＜a ＜﹣2+22，故﹣2≤a ≤0；③当2a ＞-1，即a ＜﹣2时，g （x ）min ＝g （1）＝2＞0，满足，故a ＜﹣2． 综上a 的取值范围1a <，故选A.5．（2021·沂源县第二中学高一开学考试）若偶函数()f x 在(,0]-∞上是增函数，则下列关系式中成立的是（ ）A ．3(1)(2)2f f f ⎛⎫-<-< ⎪⎝⎭B ．3(1)(2)2f f f ⎛⎫-<-< ⎪⎝⎭C ．3(2)(1)2f f f ⎛⎫<-<- ⎪⎝⎭ D ．3(2)(1)2f f f ⎛⎫<-<- ⎪⎝⎭【答案】D【解析】因为()f x 为偶函数，所以(2)(2)f f =-， 又因为()f x 在(,0]-∞上是增函数，且3212<--<-， 所以3(2)(1)2f f f ⎛⎫-<-<- ⎪⎝⎭，即3(2)(1)2f f f ⎛⎫<-<- ⎪⎝⎭， 故选：D.6．（2021·长宁区·上海市延安中学高一期末）设2,0()1,0x x f x x -⎧≤=⎨>⎩，则满足()()1 2f x f x +<的实数x的取值范围是__________. 【答案】(),0-∞【解析】作出函数2,0()1,0x x f x x -⎧≤=⎨>⎩的图像如图，满足(1)(2)f x f x +<2021x x x <⎧∴⎨<+⎩，解得0x <.故答案为：(),0-∞.7．（2021·全国高一课时练习）已知函数37().2x f x x +=+ （1）判断并证明函数()f x 在()2,-+∞的单调性；（2）若函数()f x 的定义域为()2,2-且满足2(23)()f m f m -+>，求m 的范围. 【答案】（1）证明见解析，(2,)x ∈-+∞时，函数37()2x f x x +=+为减函数；（2）()1,2. 【解析】（1）371()322x f x x x +==+++，()f x 在(2,)-+∞上是减函数，证明如下： 设122x x >>-，则2112121211()()22(2)(2)x x f x f x x x x x --=-=++++， 122x x >>-，120x ∴+>，220x +>，210x x -<， 12()()f x f x ∴<，()f x ∴在(2,)-+∞上为减函数；（2）由（1）可知：当(2,2)x ∈-时，函数()f x 为减函数，∴由2(23)()f m f m -+>得，2222322223m m m m -<-+<⎧⎪-<<⎨⎪-+<⎩，解得12m <<，m ∴范围为(1,2)．【题组六 利用单调性求最值】1．（2021·广东汕头市·高一期末）设函数2()1f x mx mx =--，若对于[1,3]x ∈，()>-f x m 恒成立，则实数m 的取值范围是（ ）A ．1,7⎛⎫-∞ ⎪⎝⎭B ．(1,)+∞C ．(,1)-∞D ．1,7⎛⎫+∞ ⎪⎝⎭【答案】B【解析】当0m =时，()1f x =-，由1m ->-，得1m ，不符合题意； 当0m ≠时，函数()f x 的对称轴为12x =， 当0m >时，函数()f x 在区间[1,3]上单调递增，此时函数min ()(1)1f x f ==-， 要使[1,3]x ∈，()>-f x m 恒成立，只需1m ->-，解得1m ，所以1m ； 当0m <时，函数()f x 在区间[1,3]上单调递减，此时函数min ()(3)61f x f m ==-， 要使[1,3]x ∈，()>-f x m 恒成立，只需61m m ->-，解得17m >，不符合题意； 综上：实数m 的取值范围是(1,)+∞. 故选：B2．（2021·广东广州市·高一期末）已知函数()()221f x x ax a R =+-∈，若()1,2x ∀∈，()0f x ≤，则a 的取值范围是_________. 【答案】7,2⎛⎤-∞- ⎥⎝⎦【解析】()1,2x ∀∈，()2021f x x ax =-≤+恒成立，即12,(1,2)a x x x≤-+∈恒成立，设1()2g x x x =-+在(1,2)单调递减，所以7()12g x -<<-， 所以72a ≤-. 故答案为：7,2⎛⎤-∞- ⎥⎝⎦. 3．（2021·浙江高一期末）（多选）已知函数222y x x -=+的值域是[1，2]，则其定义域可能是（ ）A ．[0,1]B ．[ 1,2]C ．1,24⎡⎤⎢⎥⎣⎦D ．[1,1-]【答案】ABC【解析】因为函数222y x x -=+的值域是[1，2]，由2y =可得0x =或2x =，由1y =可得1x = 所以其定义域可以为A 、B 、C 中的集合 故选：ABC4．（2021·全国高一课时练习）二次函数24y ax x a =++的最大值是3，则a =_______.【答案】1-【解析】根据题意，二次函数24y ax x a =++的最大值是3，则2041634a a a<⎧⎪⎨-=⎪⎩，解得1a =-.故答案为：1-.5．（2021·安徽省舒城中学高一开学考试）已知函数2()23f x x x =--在[]1m －，上的最大值为()f m ，则m 的取值范围是（ ）A ．(11]－， B ．(1,122]-+ C ．[122,)++∞ D ．(1,1][122,)-⋃++∞【答案】D【解析】()f x 的图象如下图：对称轴为1,(1)4x f ==，令2234x x --=，得122x =±. 因为(1)0f -=，所以数形结合可得11m -<或122m +.故选：D6（2021·云南文山壮族苗族自治州·砚山县第三高级中学高一期末）已知函数1()2f x x a =+，且1(2)5f =． （1）求a 的值；（2）试判断函数在(1,)+∞上的单调性，并给予证明；（3）求函数在[3,5]x ∈的最大值和最小值．【答案】（1）1a =，（2）减函数，证明见解析，（3）最大值17，最小值111 【解析】（1）因为1()2f x x a =+，且1(2)5f =， 所以1145a =+，解得1a =， （2）函数1()21f x x =+在(1,)+∞上为减函数，证明如下： 任取12,(1,)x x ∈+∞，且12x x <，则121211()()2121f x f x x x -=-++ 21122()(21)(21)x x x x -=++ 因为12,(1,)x x ∈+∞，且12x x <，所以210x x ->，12210,210x x +>+>， 所以12())0(f x f x ->，即12()()f x f x >，所以函数1()21f x x =+在(1,)+∞上为减函数， （3）由（2）可知1()21f x x =+在[3,5]上为减函数， 所以当3x =时，函数取得最大值，即max 11()2317f x ==⨯+， 当5x =时，函数取得最小值，即min 11()25111f x ==⨯+ 7．（2020·重庆市万州南京中学高一期中）已知函数()1=+x f x x （1）用定义法判断()f x 在区间()1,-+∞上是增函数；（2）求函数()f x 在区间[]2,5上的最值.【答案】（1）证明见解析；（2）()()min max 25,36f x f x == 【解析】(1)证明：()1111111x x f x x x x +-===-+++ 任取()12,1,x x ∈-+∞，且12x x <()()1212111111f x f x x x ⎛⎫⎛⎫-=--- ⎪ ⎪++⎝⎭⎝⎭211111x x =-++()()()()12121111x x x x +-+=++121211x x x x 121x x -<<，12120,10,10x x x x ∴-<+>+>()()120f x f x ∴-<，即()()12f x f x <∴()f x 在()1,-+∞单调递增（2）由（1）知，()f x 在[]2,5单调递增，()()()()min max 252,536f x f f x f ∴==== 8．（2021·深圳第二外国语学校高一期末）已知函数1()2f x x x=+. （1）证明：证明函数()f x 在区间2,2⎛⎫+∞ ⎪ ⎪⎝⎭上单调递增；（2）若2()31f x a a ≥+-在[]1,3x ∈上恒成立，求实数a 的取值范围. 【答案】（1）证明见解析；（2）41a -≤≤.【解析】（1）任取1222x x <<，∴1212121122f x f x x x x x ()12121221x x x x x x -=-， ∵1222x x <<，∴120x x -<，12210x x ->，120x x >， ∴()()120f x f x -<， 故函数()f x 在区间2,2⎛⎫+∞ ⎪ ⎪⎝⎭上单调递增； （2）2()31f x a a ≥+-在[]1,3x ∈上恒成立，等价于2min 31()a a f x +-≤， 由（1）知()f x 在[]1,3x ∈单调递增，∴()min ()13f x f ==，∴2313a a +-≤，解得41a -≤≤.9．（2021·海南鑫源高级中学高一期末）一次函数()2(0)f x kx a =+≠且(1)5f =.（1）求k 的值；（2）证明()f x 在R 上单调递增.【答案】（1）3k =；（2）证明见解析.【解析】（1）一次函数()2(0)f x kx a =+≠且(1)5f =.则25k +=，则3k =.（2）证明：由（1）得()32f x x =+，在R 上任取1x ，2x ，令12x x <，则()1212()()3232f x f x x x -=+-+()123x x =- 12x x <，12()()0f x f x ∴-<，()f x ∴在R 上是单调递增函数．10．（2021·安徽高一开学考试）已知函数22()x f x x-=.（1）判断()f x 在(0,)+∞上的单调性，并用定义法证明；（2）已知()f x 在[]1,2上的最大值为m ，若正实数a ，b 满足ab m =，求11a b +最小值. 【答案】（1）()f x 在(0,)+∞上单调递增，证明见解析；（2）2.【解析】（1）函数()f x 在(0,+)∞上单调递增. 证明如下： 令120x x >>，()()2212121212212222x x f x f x x x x x x x ---=-=-+- ()121221x x x x ⎛⎫=-+ ⎪⎝⎭. 因为120x x >>，所以120x x ->，120x x >，所以12122()(1)0x x x x -+>， 所以()()120f x f x ->，即()()12f x f x >，所以函数()f x 在(0,)+∞上单调递增.（2）由（1）知函数()f x 在(0,)+∞上单调递增，所以函数()f x 在[]1,2上的最大值为222(2)12f -==， 即1m =，所以1ab =，所以1122a b a b ab a b ab++==+≥=， 当且仅当1a b ==时等号成立. 11．（2021·福建三明市·高一期末）已知函数21()1x f x x -=+． （1）判断()f x 在[)0,+∞上单调递增还是单调递减，并证明你的判断；（2）若[]1,x m ∈，()f x 的最大值与最小值的差为12，求m 的值．【答案】（1）()f x 在[)0,+∞上单调递增，证明见解析；（2）2m =.【解析】（1）()f x 在[)0,+∞上单调递增，证明如下：设任意的120x x ≤<，则()()()()121212121232121()1111x x x x f x f x x x x x ----=-=++++， 因为120x x ≤<，故120x x -<，()()12110x x ++>，故()12()0f x f x -<即()12()f x f x <，故()f x 在[)0,+∞上单调递增.（2）由（1）可知()f x 在[]1,m 上为增函数，故()()()()min max 1211,,21m f x f f x f m m -====+ 所以2111122m m --=+，故2m =，此时1m 符合， 故2m =.。

舒城中学2020学年度第一学期第四次统考高一英语第一部分听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What is the man going to do on Sunday?A.Visit his mother.B. Do some gardeningC. Move into a new house.2. What does the man think of the building might be?A. An apartment building.B. A hotel.C. A department store.3. Where does the conversation take place?A. In a store.B. In a bank.C. In a classroom.4. When will the next bus come?A. At 6:35.B. At 6:45.C. At 7:00.5. When does the conversation probably take place?A. At 4:30 p.mB. At 5: 00 p.m.C. At 5:30 p.m. 第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料，回答第6、7题。

6. What’s the probable relationship between the speakers?A. FriendsB. Neighbors.C. Customer and waitress.7. How will Bill and Mary go home?A. By busB. By taxiC. By subway.听第7段材料，回答第8、9题。

安徽省六安市舒城中学2019-2020学年高一英语上学期第一次月考试题（总分：150分时间：120分钟）第一部分：听力理解（共两节，满分30分）第一节 (共 5 小题；每小题 1.5 分，满分 7.5 分)听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. Which city does the man like the most?A. Rome.B. Paris.C. New York.2. What's the season in Australia now?A. Summer.B. Winter.C. Spring.3. What does the man invite the woman to do on Saturday?A. Go to an art show.B. Visit his friend.C.Seehispaintings.4. How many eggs does the woman need today?B. Ten.C. Twenty. A. Forty.5. Where does the conversation take place?A. In a hospital.B. In a supermarket.C. In a restaurant.)分分，满分共第二节 ( 15 小题；每小题 1.5 22.5三个选项听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的ACB、、秒钟；听完后，中选出最佳选项。

听每段对话或独白前，你将有时间阅读各个小题，每小题5 各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

、段材料，回答第听第667题。

6. What sport does Janice like best?C. Tennis.A. Soccer.B. Baseball.7. What will Jim do this afternoon?- 1 -A. Play ball games.B. Visit his friends.C. Go to the tennis club听第7段材料，回答第8、9题。

安徽省六安市舒城中学2020-2021学年高一英语下学期开学考试试题时间：120分钟总分：150分第Ⅰ卷第一部分听力（共两节，满分30分）做题时，先将答案标在试卷上，录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一部分听力（共20题，每小题1.5分，共30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的指定位置处。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What will the speakers do?A. Stay away for a couple of weeks.B. Look after Johnson’s house.C. Move to another place.2. What do the speakers hurry to do?A. Play football.B. Go bird-watching.C. Buy tickets.3. What is the woman surprised at?A. A news story.B. The man’s discovery.C. The man’s behavior.4. What are the speakers arguing about?A. The importance of liberation.B. The position of women in society.C. The necessity of career planning.5. Why doesn’t the woman hire a gardener?A. To enjoy the extra exercise.B. To kill the spare time.C. To cut down the expenses.第二节(共15小题，每小题l．5分，满分22．5分)听下面5段对话或独白。

舒城中学2021—2022学年度第一学期第一次统考高一英语命题：审校：总分：150分时间：120分钟第Ⅰ卷(100分）第一部分听力（共两节，满分30分）第一节(共5小题；每小题1. 5分，满分7. 5分)听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1．What does the man think of the film?A．Very good.B．Very bad. C．Not too bad.2．Where does the conversation most probably take place?A．At a railway station. B．At an airport. C．In a classroom.3．How often does the woman's daughter go to the Chinese restaurant?A．Once a month. B．Every day. C．Once a week.4．How much should the man pay for the tickets?A．$ 28. B．$ 35. C．$ 42.5．What can we learn from this conversation?A．The woman was trying to sleep.B．The woman was making a loud noise.C．The man was trying to sleep.其次节（共15小题，每小题1.5分，满分22.5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。

安徽省六安市舒城县2021-2021学年高一英语上学期周考试题〔五〕〔无答案〕第一局部阅读理解〔共两节，总分值40分〕第一节〔共15小题; 每题2分，总分值30分〕阅读以下短文，从每题所给的四个选项〔A 、B 、C 和 D 〕中，选出最正确选项，并在答题卡上将该项涂黑。

AWhere can you go to listen to important people talk about important subjects? BigThink is a new website that allows Internet users to discuss certain topics with world experts (专家). Subjects discussed on BigThink include the environment, music and questions about happiness and personal identity. The website has been called a YouTube for thinkers. Victoria Brown and Peter Hopkins created BigThink . They said that people needed an international place to communicate with each other and discuss the important issues (话题) of our times. On the BigThink website, when you click on a subject, you will find a video of a person talking about his or her ideas. For example, you can listen to United States Senator Ted Kennedy talking about education and other things. Besides, you can read the comments and questions written by other visitors to the website. More than one hundred experts have expressed their ideas on the website. BigThink’s creators (创建者) started the website by first getting famous people to agree to be videoed. They began by interviewing several well-known professors from Harvard University. Then they used the names of these professors to gain the trust of others and get them to take part in the project. The website says BigThink belongs to everyone. Its motto (格言) is: "We are what you think." So, go online and start thinking big.1．BigThink was created to ______.A. discuss important peopleB. show Internet users funny videosC. introduce the latest IT knowledge and help Internet users solve problemsD. offer Internet users the chance to communicate with experts2．If you visit BigThink , you can ______.A. listen to your favorite musicB. chat with thinkers face to face onlineC. communicate with people worldwideD. get an online education3．Why did the creators of BigThink start interviewing famous people?A. To get their agreement to be videoed.B. To gain their trust for the website.C. To attract people’s attention to the website.D. To use their names in discussions.4．What’s the text mainly about?A. How to set up one’s own website.B. A brief introduction to BigThink .C. What to do on BigThink .D. The importance of sharing ideas with others.BThe Diet Zone: A Dangerous PlaceDiet Coke, diet Pepsi, diet pills, no-fat diet, vegetable diet… We are surrounded by the word “diet〞everywhere we look and listen．We have so easily been attracted by the promise and potential of diet products that we have stopped thinking about what diet products are doing to us．We are paying for products that harm us psychologically and physically．Diet products significantly weaken us psychologically．On one level, we are not allowing our brain to admit that our weight problems lie not in actually losing the weight, but in controlling the consumption of fatty, high-calorie, unhealthy foods．Diet products allow us to jump over the thinking stage and go straight for the scale〔秤〕instead．All we have to do is to swallow or recognize the word “diet〞 in food labels．On another level, diet products have greater psychological effects．Every time we have a zero-calorie drink, we are telling ourselves without our awareness that we don’t have to work to get results．Diet products make people believe that gain comes without pain, and that life can be without resistance and struggle．The danger of diet products lies not only in the psychological effects they have on us, but also in the physical harm that they cause．Diet foods can indirectly harm our bodies because consuming them instead of healthy foods means we are preventing our bodies from having basic nutrients．Diet foods and diet pills contain zero calorie only because the diet industry has created chemicals to produce these wonder products．Diet products may not be nutritional, and the chemical that go into diet products are potentially dangerous．Now that we are aware of the effects that diet products have on us, it is time to seriously think about buying them．Losing weight lies in the power of minds, not in the power of chemicals．Once we realize this, we will be much better able to resist diet products, and therefore prevent the psychological and physical harm that comes from using them．5．From Paragraph 1, we learn that ________．A．diet products fail to bring out peopl e’s potentialB．people have difficulty in choosing diet productsC．diet products are misleading peopleD．people are fed up with diet products 6．One psychological effect of diet products is that people tend to _____．A．try out a variety of diet foodsB．hesitate before they enjoy diet foodsC．pay attention to their own eating habits高一英语第1页(共8页)D．watch their weight rather than their diet7．In Paragraph 3, “gain comes without pain〞probably means ______．A．losing weight is effortlessB．it costs a lot to lose weight C．diet products bring no painD．diet products are free from calories8．Diet products indirectly harm people physically because such products ______．A．are over-consumedB．lack basic nutrientsC．are short of chemicalsD．provide too much energyCWorldwide, the most people willing to return your mobile phone if you’ve lost it are to be found in Slovenia, and the fewest in Malaysia. This finding is the result of an interesting study in 32 of the world’s largest cities. Altogether, researchers "lost"960 new mobile phones. They got back 654 of them, or 68 percent. Prague came in at number eight. There, 23 out of 30 people who were willing to return the mobile phone.It wasn’t a traditional study. Two researchers carefully chose different places, such as areas with high crime (犯法) and busy downtown shopping areas, to "lose" the phones. When one of the researchers dropped a phone, the other would keep watching from a distance. The honest finders tried their best to find the owner with the help of the address book in the phone. They were told why the study was done and asked why they acted the way they did.It was found that the busier the place where the researchers dropped the phone, the greater the chance of it being returned. Another interesting finding was that women were generally more likely than men to return the phone. Researchers also found that most people still have a sense of honesty. "Crime is simply not good behaviour (行为),"said an expert. "People want to trust others, and want to be trusted."9． Who would be most likely to return a phone, according to the study?A. A man who found it in a park.B. A woman who found it in a park.C. A man who found it in a shopping center.D. A woman who found it in a shopping center.10．Which of the following are findings of the study?a. Prague placed number 8 among the 32 cities.b. Men were less likely to return phones than women.c. It was a traditional and interesting study.d. The busier the place, the greater the chance of the phone being returned.A. abcB. bcdC. acdD. abd11．Why did most people return the phones?A. They knew they belonged to the researchers.B. They wanted to be normal people.C. They wanted to be trusted.D. They didn’t want to commit a crime.12．This passage is mainly about ______.A. why most people returned the phonesB. whether people in busier places are more honestC. a study of people’s honestyD. the honesty of people who return phonesDTell a story and tell it well, and you may open wide the eyes of a child, open up lines of communication in a business, or even open people’s mind to another culture or race.People in many places are digging up theold folk stories and the messages in them. For example, most American storytellers get their tales from a wide variety of sources, cultures, and times. They regard storytelling not only as a useful tool in child education, but also as a meaningful activity that helps adults understand themselves as well as those whose culture may be very different from their own.“Most local stories are based on a larger theme,〞 American storyteller Opalanga Pugh says, “Cinderella, or the central idea of a good child protected by her goodness, appears in various forms in almost every culture of the world.〞Working with students in schools, Pugh helps them understand their own cultures and the general messages of the stories. She works with prisoners too, helping them knowing who they are by telling stories that her listeners can write, direct, and act in their own lives. If they don’t like the story they are living, they can rewrite the story. Pugh also works to help open up lines of communication between managers and workers. “For every advance in business,〞 she says, “there is a greater need for communication〞. Storytelling can have a great effect on either side of the manager-worker relationship, she says.Pugh spent several years in Nigeria, where she learned how closely storytelling was linked to the everyday life of the people there. “The benefits of storytelling are found everywhere,〞 she says.“I learned how people used stories to spread their culture,〞she says, “What I do is to focus on the value of the stories that people can translate into their own daily world of affairs. We are all storytellers. We all have a story to tell. We tell everybody’s story.〞13．What do we learn about American storyteller from Paragraph 2?A. They share the same way of storytelling.B. They prefer to tell the stories from other cultures.C. They learn their stories from the American natives.D. They find storytelling useful for both children and adults.14．The underlined sentence (Paragraph 4) suggests that prisoners can _____.A. start a new lifeB. settle down in another placeC. direct filmsD. become good actors15．Pugh has practiced storytelling with _____ groups of people.A. 2B. 3C. 4D. 5第二节〔共5小题；每题2分，总分值10分〕按照短文内容，从短文后的选项当选出能填入空白处的最正确选项。