Java程序设计基础第五章精品PPT课件
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Java语言程序设计_基础篇_中文ppt_第五章第5章方法Liang,IntroductiontoJavaProgramming,EighthEdition,(c)2022Pearon Education,Inc.Allrightreerved.0132130807开放问题分别求出1到10、20到30、35到45的整数和。
Liang,IntroductiontoJavaProgramming,EighthEdition,(c)2022Pearon Education,Inc.Allrightreerved.0132130807问题intum=0;for(inti=1;i<=10;i++)um+=i;Sytem.out.println("Sumfrom1to 10i"+um);um=0;for(inti=20;i<=30;i++)um+=i;Sytem.out.println("Sum from20to30i"+um);um=0;for(inti=35;i<=45;i++)um+=i;Sytem.out.prin tln("Sumfrom35to45i"+um);Liang,IntroductiontoJavaProgramming,EighthEdition,(c)2022Pearon Education,Inc.Allrightreerved.0132130807问题intum=0;for(inti=1;i<=10;i++)um+=i;Sytem.out.println("Sumfrom1to 10i"+um);um=0;for(inti=20;i<=30;i++)um+=i;Sytem.out.println("Sum from20to30i"+um);um=0;for(inti=35;i<=45;i++)um+=i;Sytem.out.prin tln("Sumfrom35to45i"+um);Liang,IntroductiontoJavaProgramming,EighthEdition,(c)2022Pearon Education,Inc.Allrightreerved.0132130807解决方案publictaticintum(inti1,inti2){intum=0;for(inti=i1;i<=i2;i++)um+ =i;returnum;}publictaticvoidmain(String[]arg){Sytem.out.println("Sumfrom1to10i"+um(1,10));Sytem.out.println("Sumfrom20to30i"+u m(20,30));Sytem.out.println("Sumfrom35to45i"+um(35,45));}Liang, IntroductiontoJavaProgramming,EighthEdition,(c)2022PearonEducat ion,Inc.Allrightreerved.0132130807学习目标定义方法、调用方法以及传参数给方法(第5.2-5.5节)。