2020年山东临沂实验学校高考模拟卷14

2020年山东临沂实验学校高考模拟卷(十)英语（考试时间：100分钟）注意事项：1.答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。

2.回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

回答非选择题时，将答案写在答题卡上，写在本试卷上无效。

3.考试结束后，将本试卷和答题卡一并交回。

第一部分阅读理解（共两节，满分50分）第一节（共15小题；每小题2.5分，满分37.5分）阅读下列短文，从每题所给的A、B、C和D四个选项中，选出最佳选项。

ATheaters of the PastThe Greek TheaterTheaters developed in many parts of Greece.Ancient Greek theaters were built in natural open air sites on conveniently shaped hills.This allowed a great mass of people to enjoy a show at a time.Due to this,actors placed emphasis on exaggerated(夸张的)action and speech.And,colorful symbolic masks and costumes were used.The Medieval TheaterThe Medieval theater started in churches.That’s why medieval plays were about Bible stories.At first,it became a custom for priests(牧师)to act out brief scenes during Christmas and Easter.These acts attracted large crowds. Finally the church refused to allow priests to participate in any such events again,so ordinary people began these performances outside.Performances were set in the town square,with several stage settings around it.The Elizabethan TheaterThe England’s theater developed rapidly in the years following the defeat of the Spanish Navy.The dominant feature of Elizabethan theater was the stage,It has three parts:The fore stage for outside scenes;the inner stage for scenes inside a building;an upper stage or balcony for various purposes.The reason for this design is that there were no scene changes,or breaks during the play.Very little scenery was used,so the actors had to create a scene through their voices and dialogues.This led to a more poetic script,and poets became the main source of script writing.The Restoration TheaterSome of the plays told sad stories,but the majority of the plays were really funny.Many specialized machines were used to create the scene.The stage was a very clever idea,in that on the sides of the stage large back shutters(百叶窗) were painted with the scene.1.Why were ancient Greek theaters built on hills?A.To hold a large audience.B.To build a big and strong stage.C.To have a better sound effect.D.To emphasize exaggerated performances.2.In which theater could actors’voices and speech help create scenes?A.The Greek Theater.B.The Medieval Theater.C.The Elizabethan Theater.D.The Restoration Theater.3.What is special about The Restoration Theater?A.Colorful masks were used.B.The stage was smartly designed.C.Most of its plays were sorrowful.D.Ordinary people were the performers.BA new family moved in next door and I got to meet the mother of the family,Lydia.Lydia is Korean,and her family moved to our city so her husband could go to graduate school.We started talking,and she was apologetic about how bad her English was,but I didn’t care.I knew how hard it was to learn a second language.I enjoyed chatting with Lydia as we watched our kids play.It was what came next that challenged me:Lydia asked if I’d be willing to help her with her English.Now,I am not a teacher.I admire teachers,and I’m grateful for teachers,and it’s because I admire what they do so much that I was very very sure that I couldn’t do it myself.But Lydia was sure that she wanted my help.I was doubtful.I wasn’t sure my“help”was even worth being called by that name.But because she asked me,I said“yes.”And that was the beginning of a friendship.Lydia and I spent afternoons sitting together and reading the newspaper,and as we did,she asked me questions when she had them—questions about language,yes,but also questions about the new culture she found herself in.In turn,I asked my own questions,growing curious about her home country and culture.We bonded over our shared faith and our struggles as mothers of kids with special needs.When I complimented(恭维)her cooking,she began to teach me about Korean food,eventually leading to a shared trip to explore the Korean grocery stores in our city.Because of Lydia,I learned more about my own hometown than I ever could have learned by myself.I’m still not sure that I’m any good as a teacher.But I’m grateful I said“yes”when my neighbor asked me to help her with her English.That meant spending extra time with my neighbor,and that extra time meant she didn’t remain just my neighbor.She became my friend.4.What was Lydia sorry about?A.Her bad English.B.Her carelessness.C.Nobody teaching her English.D.Her poor life in a new place.5.What can be concluded from the third paragraph?A.The author admired teachers.B.The author wanted to be a teacher.C.The author didn’t want to help Lydia.D.The author was not confident in helping Lydia.6.Why was the author grateful at the last paragraph?A.She managed to learn English well.B.She made friends with her neighbor.C.She learned how to cook Korean food.D.She realized her dream of being a teacher.7.What can we learn from the passage?A.No pains,no gains.B.A friend in need is a friend indeed.C.To help others is to help ourselves.D.Where there is a will,there is a way.CWeChat is a social mobile application with voice and text messaging timeline and several social features like “Message in a Bottle”.WeChat,a popular instant messaging tool run by Tencent Holdings,aims to help users access mobile services without downloading separate apps,which experts said may challenge the business of smartphone app distributors such Apple Store.This new feature,named“Mini Programs”,allows WeChat users to find a variety of services such as ticket buying by scanning a QR(quick-response)code,saving them the trouble of installing a number of different apps on smart devices,according to the transcript of a speech by Zhang Xiaolong,Tencent’s senior executive vice president, on Wednesday.The new function is expected to come online on January9.Zhang,known as the father of WeChat,emphasized that“Mini Programs”is not a mobile app distributing function.Still,experts and app developers said that the rollout(推出)of“Mini Programs”on WeChat will erode the market share of app distributors like Apple Store in China.“‘Mini Programs’will attract lots of start-ups,because a program based on WeChat can help them build up businesses at much lower costs,”a Shanghai-based app developer,told the Global Times on Wednesday.If a start-up wants to promote its business via a separate application,it has to hire a special team to develop two different apps—one each for IOS and Android.Launched in2011,WeChat has evolved to include services such as“Order Taxi”,“Food Delivery”,e-commerce and payments from just an instant messaging app.8.What can we know about“Mini Programs”?A.It’s expensive.B.It’s complex.C.It’s convenient.D.It’s free.9.Why do lots of start-ups choose the“Mini Programs”?A.It can cut the costs of building business.B.It can help build up business.C.It can help them make a big fortune.D.It can promote their business.10.What does the underlined word“erode”probably mean in Paragraph4?A.Increase.B.Reduce.C.Improve.D.Promote.11.What can be inferred from the last paragraph?A.WeChat will be a perfect app.B.WeChat will meet a great challenge.C.WeChat will meet needs of more people.D.WeChat will replace other apps.DIn my memory,winters always used to be really unpleasant.You had to bundle up just to keep warm when you went outside.You were often cold,wet,slip on the ice,and you’d arrive home to an ice-cold house.And that would mean turning on the heating and waiting.It’s a miracle you didn’t get cold to the bone.Fortunately,things don’t have to be so challenging any more.Technology,engineering and design have advanced giving us new solutions to old problems.It means dealing with winter needn’t be like skating on thin ice. With a smart thermostat(温度自动调节器),our homes can be warm when we need them to be.Many models feature smartphone apps that allow you to control temperature remotely,so we can warm up the house before we arrive home.According to ,Tado’s model features voice control,while the Nest‘leans’your habits and automatically heats the home for you.Clothes have been given an upgrade,too.Electronic thermal jackets,sweaters and coats heat up when you turnthem on.What is the better way to keep warm in the dead of winter?At the touch of a button,or through an app on our phones,the clothing generates heat from elements placed inside.Many models offer three levels of heating which stay warm for over12hours.Finally,there is the clothing for the head,Beanies and Earmuffs,that feature speakers included in the fabric using Bluetooth technology so we can listen to our favourite music or,in some cases,have a phone call using the in-built microphone.All while keeping the head warm and avoiding a cold.For many,the thought of winter used to be enough to make their blood run cold.But using technology,life needn’t freeze up.With the right solutions,there’s no reason why winter can’t be really,really cool.12.What do the underlined words“bundle up”mean in Para.1?A.Fix an air conditioner.B.Take a hot bath.C.Run a lot.D.Put on more clothes.13.How does electronic thermal clothing work?A.The equipment placed inside the clothing produces heat.B.It needs to be warmed up before being used.C.The thermostat heats up automatically when the temperature is low.D.It keeps warm for over12hours after being charged for an hour.14.From the passage,we can learn the following statements EXCEPT that______.A.Tado’s model can be controlled by saying something to itB.with the in-built speaker and microphone,Beanies and Earmuffs users can have a phone callC.technology can do nothing to make winter less roughD.Bluetooth technology is used in the clothing for the head15.What’s the best title of this passage?A.A Smart ThermostatB.A Modern WinterC.Ways of Keeping WarmD.An Unpleasant Winter第二节(共5小题；每小题2.5分，满分12.5分)根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

山东省临沂实验学校2020年高考英语模拟卷（十）（考试时间：100 分钟）注意事项：1.答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。

2.回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

回答非选择题时，将答案写在答题卡上，写在本试卷上无效。

3.考试结束后，将本试卷和答题卡一并交回。

第一部分阅读理解（共两节，满分50 分）第一节（共15 小题；每小题 2.5 分，满分 37.5 分）阅读下列短文，从每题所给的 A、B、C 和 D 四个选项中，选出最佳选项。

ATheaters of the PastThe Greek TheaterTheaters developed in many parts of Greece. Ancient Greek theaters were built in natural open air sites on conveniently shaped hills. This allowed a great mass of people to enjoy a show at a time. Due to this, actors placed emphasis on exaggerated(夸张的) action and speech. And, colorful symbolic masks and costumes were used.The Medieval TheaterThe Medieval theater started in churches. That’s why medieval plays were about Bible stories. At first, it became a custom for priests ( 牧师 ) to act out brief scenes during Christmas and Easter. These acts attracted large crowds. Finally the church refused to allow priests to participate in any such events again, so ordinary people began these performances outside. Performances were set in the town square, with several stage settings around it.The Elizabethan TheaterThe England’s theater developed rapidly in the years following the defeat of the Spanish Navy. The dominant feature of Elizabethan theater was the stage, It has three parts : The fore stage for outside scenes ; the inner stage for scenes inside a building; an upper stage or balcony for various purposes. The reason for this design is that there were no scene changes, or breaks during the play. Very little scenery was used, so the actors had to create a scene through their voices and dialogues. This led to a more poetic script, and poets became the main source of script writing.The Restoration TheaterSome of the plays told sad stories, but the majority of the plays were really funny. Many specialized machines were used to create the scene. The stage was a very clever idea, in that on the sides of the stage large back shutters(百叶窗) were painted with the scene.1.Why were ancient Greek theaters built on hills?A.To hold a large audience.B.To build a big and strong stage.C.To have a better sound effect.D.To emphasize exaggerated performances.2.In which theater could actors’ voices and speech help create scenes?A.The Greek Theater.B.The Medieval Theater.C.The Elizabethan Theater.D.The Restoration Theater.3.What is special about The Restoration Theater?A.Colorful masks were used.B.The stage was smartly designed.C.Most of its plays were sorrowful.D.Ordinary people were the performers.BA new family moved in next door and I got to meet the mother of the family, Lydia. Lydia is Korean, and her family moved to our city so her husband could go to graduate school. We started talking, and she was apologetic about how bad her English was, but I didn’t care. I knew how hard it was to learn a second language. I enjoyed chatting with Lydia as we watched our kids play.It was what came next that challenged me: Lydia asked if I’d be willing to help her with her English. Now, I am not a teacher. I admire teachers, and I’m grateful for teachers, and it’s because I admire what they do so much that I was very very sure that I couldn’t do it myself.But Lydia was sure that she wanted my help. I was doubtful. I wasn’t sure my “help” was even worth being called by that name. But because she asked me, I said “yes. ” And that was the beginning of a friendship. Lydia and I spent afternoons sitting together and reading the newspaper, and as we did, she asked me questions when she had them—questions about language, yes, but also questions about the new culture she found herself in. In turn, I asked my own questions, growing curious about her home country and culture. We bonded over our shared faith and our struggles as mothers of kids with special needs. When I complimented( 恭维) her cooking, she began to teach me about Korean food, eventually leading to a shared trip to explore the Korean grocery stores in our city. Because of Lydia, I learned more about my own hometown than I ever could have learned by myself. I’m still not sure that I’m any good as a teacher. But I’m grateful I said “yes” when my neighbor asked me to help her with her English. That meant spending extra time with my neighbor, and that extra time meant she didn’t remain just my neighbor. She became my friend.4.What was Lydia sorry about?A.Her bad English.B.Her carelessness.C.Nobody teaching her English.D.Her poor life in a new place.5.What can be concluded from the third paragraph?A.The author admired teachers.B.The author wanted to be a teacher.C.The author didn’t want to help Lydia.D.The author was not confident in helping Lydia.6.Why was the author grateful at the last paragraph?A.She managed to learn English well.B.She made friends with her neighbor.C.She learned how to cook Korean food.D.She realized her dream of being a teacher.7.What can we learn from the passage?A.No pains, no gains.B.A friend in need is a friend indeed.C.To help others is to help ourselves.D.Where there is a will, there is a way.CWeChat is a social mobile application with voice and text messaging timeline and several social features like “Message in a Bottle”. WeChat, a popular instant messaging tool run by Tencent Holdings, aims to help users access mobile services without downloading separate apps, which experts said may challenge the business of smartphone app distributors such Apple Store.This new feature, named “Mini Programs”, allows WeChat users to find a variety of services such as ticket buying by scanning a QR (quick-response) code, saving them the trouble of installing a number of different apps on smart devices, according to the transcript of a speech by Zhang Xiaolong, Tencent’s senior executive vice president, on Wednesday. The new function is expected to come online on January 9.Zhang, known as the father of WeChat, emphasized that “Mini Programs” is not a mobile app distributing function.Still, experts and app developers said that the rollout ( 推出) of “Mini Programs” on WeChat will erode themarket share of app distributors like Apple Store in China.“‘Mini Programs’ will attract lots of start-ups, because a program based on WeChat can help them build up businesses at much lower costs, ” a Shanghai-based app developer, told the Global Times on Wednesday.If a start-up wants to promote its business via a separate application, it has to hire a special team to develop two different apps—one each for IOS and Android.Launched in 2011, WeChat has evolved to include services such as “Order Taxi”, “Food Delivery”, e-commerce and payments from just an instant messaging app.8.What can we know about “Mini Programs”?A. It’s expensive.B. It’s complex.C. It’s convenient.D. It’s free.9.Why do lots of start-ups choose the “Mini Programs”?A.It can cut the costs of building business.B.It can help build up business.C.It can help them make a big fortune.D.It can promote their business.10.What does the underlined word “erode” probably mean in Paragraph 4?A. Increase.B. Reduce.C. Improve.D. Promote.11.What can be inferred from the last paragraph?A.WeChat will be a perfect app.B.WeChat will meet a great challenge.C.WeChat will meet needs of more people.D.WeChat will replace other apps.DIn my memory, winters always used to be really unpleasant. You had to bundle up just to keep warm when you went outside. You were often cold, wet, slip on the ice, and you’d arrive home to an ice-cold house. And that would mean turning on the heating and waiting. It’s a miracle you didn’t get cold to the bone.Fortunately, things don’t have to be so challenging any more. Technology, engineering anddesign have advanced giving us new solutions to old problems. It means dealing with winter needn’t be like skating on thin ice.With a smart thermostat ( 温度自动调节器), our homes can be warm when we need them to be. Many modelsfeature smartphone apps that allow you to control temperature remotely, so we can warm up the house before we arrive home. According to techradar. com, Tado’s model features voice control, while the Nest ‘leans’ your habits and automatically heats the home for you.Clothes have been given an upgrade, too. Electronic thermal jackets, sweaters and coats heat up when you turnthem on. What is the better way to keep warm in the dead of winter? At the touch of a button, or through an app on our phones, the clothing generates heat from elements placed inside. Many models offer three levels of heating which stay warm for over 12 hours.Finally, there is the clothing for the head, Beanies and Earmuffs, that feature speakers included in the fabric using Bluetooth technology so we can listen to our favourite music or, in some cases, have a phone call using the in-built microphone. All while keeping the head warm and avoiding a cold.For many, the thought of winter used to be enough to make their blood run cold. But using technology, life needn’t freeze up. With the right solutions, there’s no reason why winter can’t be really, really cool.12.What do the underlined words “bundle up” mean in Para. 1?A. Fix an air conditioner.B. Take a hot bath.C. Run a lot.D. Put on more clothes.13.How does electronic thermal clothing work?A.The equipment placed inside the clothing produces heat.B.It needs to be warmed up before being used.C.The thermostat heats up automatically when the temperature is low.D.It keeps warm for over 12 hours after being charged for an hour.14.From the passage, we can learn the following statements EXCEPT that .A.Tado’s model can be controlled by saying something to itB.with the in-built speaker and microphone, Beanies and Earmuffs users can have a phone callC.technology can do nothing to make winter less roughD.Bluetooth technology is used in the clothing for the head15.What’s the best title of this passage?A.A Smart ThermostatB.A Modern WinterC.Ways of Keeping WarmD.An Unpleasant Winter第二节 (共 5 小题；每小题 2.5 分，满分 12.5 分)根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

山东省临沂市2020届高三一模语文试题及答案临沂市2020届高手年级检测语文试题2020.4本试卷共23题,共150分,共10页注意事项：1.答卷前,考生务必将自己的姓名、准考证号填写在答题卡上,并将准考证条形码黏贴在答题卡上的指定位置。

2.选择题的作答:选出每小题答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。

写在试卷、草稿纸和答题卡上的非答题区域均无效。

3.非选择题的作答:用黑色签字笔直接答在答题卡上对应的答题区域内。

写在试卷、草稿纸和答题卡上的非答题区域均无效。

4.考试结束后,将本试卷和答题卡一并交回。

一、现代文阅读(35分一)现代文阅读I(本题共5小题,19分)阅读下面的文字,完成1-5题材料一中国动物卫生与流行病学中心研究员XXX通知《中国科学报》,没有切实的证据证明SARS病毒是人为制造的。

可是,我们也不能彻底排除人为制造的大概。

“首先,有不少实验室,包孕美国、欧洲或中国数十家实验室,能够人为制造多种危害极大的病毒,而且人为制造这些病毒不需要特殊材料和设施设备,费用也很少。

”他说。

一些科学不端、不察行为,甚至有组织的科学不端、不察行为,屡见不鲜,这也导致人们对现今很多新发的传染性疾病有越来越多怀疑。

“比如2009年导致全球流感大流行的病毒,就被人们怀疑是人为制造的,”XXX说,“这是因为至今未发现这个基因组上看似猪的病毒确实来自猪群的实际证据。

而且这个病毒的‘父亲’和‘母亲’历来分居在欧亚和北美两处,至今也没有发现它们在‘同居’的迹象,那么它们生下这个‘孽子’的概率应该很小。

”此外,有不少危害极大的病毒,包括埃博拉病毒、SARS病毒、尼帕病毒,能够在人群中快速传播H5N1亚型的禽流感病毒,以及1918年引起全球数千万人死亡的、对人有神经毒性的HN1亚型流感病毒等,都被一些实验室复制出来了;这类行为已经遭受诸多人士的广泛关注,甚至谴责。

XXX微生物流行病研究所所长XXX表示,在2004年实验室感染事件发生后,有人就说SARS是源于实验室泄漏。

2020年普通高考模拟考试理科数学一、选择题•在每小题给出的四个选项中，只有一项是符合题目要求的.1.设集合A xlnx 1，B 2, 1,0,1,2,3，则AI B （）A. 1B. 1,2C. 2, 1,0,1D. 2【答案】B【解析】【分析】首先求得集合A,然后进行交集运算即可.【详解】求解对数不等式可得 A x|0 x e ，结合题意和交集的定义可知：AI B 1,2 .故选：B【点睛】本题主要考查对数不等式的解法，交集的运算等知识，意在考查学生的转化能力和计算求解能力•2.已知复数z满足z i i 2 i，则|Z （）A. B. ,3 C. .5 D. ,10【答案】A【解析】【分析】首先求得复数z,然后求解其共轭复数并确定模即可.【详解】由题意可得：z J i 2i 1 i 1 i，i则z 1 i,|z| 72.故选：A【点睛】本题主要考查复数的运算法则，复数的模的计算等知识，意在考查学生的转化能力和计算求解能力.3.2020年之间，受益于基础设施建设对光纤产品的需求，以及个人计算机及智能手机的下一代规格升级，电动汽车及物联网等新机遇，连接器行业增长呈现加速状态. 根据该折线图, BO70闻50艸抑①每年市场规模量逐年增加；②增长最快的一年为2020〜2020;③这8年的增长率约为40%;④2020年至2020年每年的市场规模相对于2020年至2020年每年的市场规模，数据方差更小，变化比较平稳A. 1B. 2C. 3D. 4【答案】C【解析】【分析】由题意观察所给的折线图考查所给的结论是否正确即可【详解】考查所给的结论：①2020年的市场规模量有所下降，该说法错误；②增长最快的一年为2020〜2020,该说法正确；63 5 45 3③这8年的增长率约为635壬40%，该说法正确；45.3④2020年至2020年每年的市场规模相对于2020年至2020年每年的市场规模，数据方差更小，变化比较平稳，该说法正确.综上可得：正确的结论有3个.故选：C【点睛】本题主要考查折线图的识别，属于基础题.【答案】C 【解析】【分析】 首先画出可行域，然后求得最大值和最小值，最后求解两者之和即可 【详解】绘制不等式组表示的平面区域如图所示,目标函数即：y 2x z ，其中z 取得最大值时，其几何意义表示直线系在 据此结合目标函数的几何意义可知目标函数在点据此可知目标函数的最大值为： z max 2 2 2 6，联立直线方程： 7 2° ，可得点的坐标为： A 0,2，x y 2 0据此可知目标函数的最小值为：z min 2 0 2 2.x 2 0, 4.已知x,y 满足约束条件y 2 0,，则zx y 2 0,A. 4B. 62xy 的最大值与最小值之和为（y 轴上的截距最大，B 2,2处取得最大值,其中z 取得最小值时，其几何意义表示直线系在y 轴上的截距最小,据此结合目标A 处取得最小值,综上可得：z 2x y的最大值与最小值之和为8.故选：C【点睛】求线性目标函数z = ax+ by（ab^0）的最值，当b>0时，直线过可行域且在y轴上截距最大时，z值最大，在y轴截距最小时，z值最小；当b v 0时，直线过可行域且在y 轴上截距最大时，z值最小，在y轴上截距最小时，z值最大•5.从0, 1, 2, 3这四个数中任取两个不同的数组成一个两位数，则这个两位数是偶数的概率为（）2525A.-B.—C.—D.-7799【答案】D【解析】【分析】由题意列出所有可能的结然后结合古典概型计算公式可得概率值.果，【详解】能组成两位数有：10, 12, 13, 20, 21, 23, 30, 31, 32,总共有9 种情况.其中偶数有5种情况，故组成的两位数是偶数的概率为故选：D【点睛】本题主要考查古典概型计算公式，属于中等题6.函数f x ,g X的定义域都为R，且f X是奇函数，g X是偶函数，设h x f x 1 g x 1 ，则下列结论中正确的是（）A. h x的图象关于（1,0）对称 B. h x的图象关于（1,0）对称C. h x的图象关于x 1对称 D. h x的图象关于x 1对称【答案】D【解析】h x的性质【分析】由题意结合函数的奇偶性和函数的平移特性即可确定后函数【详解】首先考查函数H x其定义域为 R ，且 H x | f x | g x |fx | g x H x , 则函数H x 为偶函数，其图像关于 y 轴对称， 将H x 的图像向左平移一个单位可得函数 h x H x 1 |fxl |gx1的图像，据此可知h x 的图象关于x 1对称. 故选：D【点睛】本题主要考查函数的奇偶性，函数图像的平移变换等知识，意在考查学生的转化能 力和计算求解能力•7.秦九韶，中国古代数学家，对中国数学乃至世界数学的发展做出了杰出贡献. 他所创立的秦几韶算法，直到今天，仍是多项式求值比较先进的算法•用秦九韶算法是将201820172016f x 2019x2018x 2017x 2x 1 化为【答案】C 【解析】2019x 2018x x 2017 x2 x 1再进行运算，在计算 f X 。

2020年山东临沂实验学校高考模拟卷（九）答案英语1.C细节理解题。

由第一段中的for me they’re real friends及They are no different to the friends I have made at home.可知,作者认为网友和现实中的朋友没有区别。

2.A推理判断题。

由第二段中的Even family members think I am a freak(不正常的人)...tendencies可推断,作者对网友的看法在他的家人看来是很奇怪的、难以理解的。

3.D细节理解题。

由第五段可知,在作者因为身体不适不能外出时网友显得尤为重要。

4.D推理判断题。

根据第一段中的Foreign groups often record in English...but only by adding the words‘o’clock,four o’clock rock’at the end可知,文中提到的这个巴西小孩可能本身不太会说英语,但是由于含有这些英语数字的歌曲不断重复播放,所以他学会了说这些数字。

5.C细节理解题。

根据第二段中的but the law seemed to be honoured more in the breaking than in the observing及such laws have very little effect可知,人们经常不遵守这项法律。

6.D推理判断题。

根据第三段中的the potential selling power that the use of English vocabulary can bring及the excellence implied by the mere use of English可知,广告中使用英语能让人感觉该产品很出色,激发人们的购买欲。

7.A写作手法题。

最后一段中通过“主动结构表达被动意义”和“保留表示复数的词尾”两个例子来说明英语对其他语言的语序或结构也有影响。

2020 年山东临沂实验学校高考模拟卷(十)英语（考试时间：100 分钟）注意事项：1.答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。

2.回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

回答非选择题时，将答案写在答题卡上，写在本试卷上无效。

3.考试结束后，将本试卷和答题卡一并交回。

第一部分阅读理解（共两节，满分50 分）第一节（共15 小题；每小题2.5 分，满分37.5 分）阅读下列短文，从每题所给的A、B、C 和D 四个选项中，选出最佳选项。

ATheaters of the PastThe Greek TheaterTheaters developed in many parts of Greece. Ancient Greek theaters were built in natural open air sites on conveniently shaped hills. This allowed a great mass of people to enjoy a show at a time. Due to this, actors placed emphasis on exaggerated(夸张的) action and speech. And, colorful symbolic masks and costumes were used.The Medieval TheaterThe Medieval theater started in churches. That’s why medieval plays were about Bible st ories. At first, it became a custom for priests ( 牧师) to act out brief scenes during Christmas and Easter. These acts attracted large crowds. Finally the church refused to allow priests to participate in any such events again, so ordinary people began these performances outside. Performances were set in the town square, with several stage settings around it.The Elizabethan TheaterThe England’s theater developed rapidly in the years following the defeat of the Spanish Navy. The dominant feature of Elizabethan theater was the stage, It has three parts : The fore stage for outside scenes ; the inner stage for scenes inside a building; an upper stage or balcony for various purposes. The reason for this design is that there were no scene changes, or breaks during the play. Very little scenery was used, so the actors had to create a scene through their voices and dialogues. This led to a more poetic script, and poets became the main source of script writing.The Restoration TheaterSome of the plays told sad stories, but the majority of the plays were really funny. Many specialized machines were used to create the scene. The stage was a very clever idea, in that on the sides of the stage large back shutters(百叶窗) were painted with the scene.1.Why were ancient Greek theaters built on hills?A.To hold a large audience.B.To build a big and strong stage.C.To have a better sound effect.D.To emphasize exaggerated performances.2.In which theater could actors’ voices and speech help create scenes?A.The Greek Theater.B.The Medieval Theater.C.The Elizabethan Theater.D.The Restoration Theater.3.What is special about The Restoration Theater?A.Colorful masks were used.B.The stage was smartly designed.C.Most of its plays were sorrowful.D.Ordinary people were the performers.BA new family moved in next door and I got to meet the mother of the family, Lydia. Lydia is Korean, and her family moved to our city so her husband could go to graduate school. We started talking, and she was apologetic about how bad her English was, but I didn’t care. I knew how hard it was to learn a second language. I enjoyed chatting with Lydia as we watched our kids play.It was what came next that challenged me: Lydia asked if I’d be willing to help her with her English. Now, I am not a teacher. I admire teachers, and I’m grateful for teachers, and it’s because I admire what they do so much that I was very very sure that I couldn’t do it myself.But Lydia was sure that she wanted my help. I was doubtful. I wasn’t sure my “help” was even worth being called by that name. But because she asked me, I said “yes. ” And that was the beginning of a friendship. Lydia and I spent afternoons sitting together and reading the newspaper, and as we did, she asked me questions when she had them—questions about language, yes, but also questions about the new culture she found herself in. In turn, I asked my own questions, growing curious about her home country and culture. We bonded over our shared faith and our struggles as mothers of kids with special needs. When I complimented( 恭维) her cooking, she began to teach me about Korean food, eventually leading to a shared trip to explore the Korean grocery stores in our city. Because of Lydia, I learned more about my own hometown than I ever could have learned by myself. I’m still not sure that I’m any good as a teacher. But I’m grateful I said “yes” when my neighbor asked me to help her with her English. That meant spen ding extra time with my neighbor, and that extra time meant she didn’t remain just my neighbor. She became my friend.4.What was Lydia sorry about?A.Her bad English.B.Her carelessness.C.Nobody teaching her English.D.Her poor life in a new place.5.What can be concluded from the third paragraph?A.The author admired teachers.B.The author wanted to be a teacher.C.The author didn’t want to help Lydia.D.The author was not confident in helping Lydia.6.Why was the author grateful at the last paragraph?A.She managed to learn English well.B.She made friends with her neighbor.C.She learned how to cook Korean food.D.She realized her dream of being a teacher.7.What can we learn from the passage?A.No pains, no gains.B.A friend in need is a friend indeed.C.To help others is to help ourselves.D.Where there is a will, there is a way.CWeChat is a social mobile application with voice and text messaging timeline and several social features like “Message in a Bottle”. WeChat, a popular instant messaging tool run by Tencent Holdings, aims to help users access mobile services without downloading separate apps, which experts said may challenge the business of smartphone app distributors such Apple Store.This new feature, named “Mini Programs”, allows WeChat users to find a variety of services such as ticket buying by scanning a QR (quick-response) code, saving them the trouble of installing a number of different apps on smart devices, according to the transcript of a speech by Zhang Xiaolong, Tencent’s senior executive vice president, on Wednesday. The new function is expected to come online on January 9.Zhang, known as the father of WeChat, emphasized that “Mini Programs” is not a mobile app distributing function.Still, experts and app developers said that the rollout ( 推出) of “Mini Programs” on WeChat will erode the market share of app distributors like Apple Store in China.“‘Mini Programs’ will attract lots of start-ups, because a program based on WeChat can help them build up businesses at much lower costs, ” a Shangh ai-based app developer, told the Global Times on Wednesday.If a start-up wants to promote its business via a separate application, it has to hire a special team to develop two different apps—one each for IOS and Android.Launched in 2011, WeChat has evolv ed to include services such as “Order Taxi”, “Food Delivery”, e-commerce and payments from just an instant messaging app.8.What can we know about “Mini Programs”?A. It’s expensive.B. It’s complex.C. It’s convenient.D. It’s free.9.Why do lots of start-ups choose the “Mini Programs”?A.It can cut the costs of building business.B.It can help build up business.C.It can help them make a big fortune.D.It can promote their business.10.What does the underlined word “erode” probably mean in Paragraph 4?A. Increase.B. Reduce.C. Improve.D. Promote.11.What can be inferred from the last paragraph?A.WeChat will be a perfect app.B.WeChat will meet a great challenge.C.WeChat will meet needs of more people.D.WeChat will replace other apps.DIn my memory, winters always used to be really unpleasant. You had to bundle up just to keep warm when you went outside. You were often cold, wet, slip on the ice, and you’d arrive home to an ice-cold house. And that would mean turning on the heating and waiting. It’s a miracle you didn’t get c old to the bone.Fortunately, things don’t have to be so challenging any more. Technology, engineering and design have advanced giving us new solutions to old problems. It means dealing with winter needn’t be like skating on thin ice. With a smart thermostat ( 温度自动调节器), our homes can be warm when we need them to be. Many models feature smartphone apps that allow you to control temperature remotely, so we can warm up the house before we arrive home. According to techradar. com, Tado’s model features voice control, while the Nest ‘leans’ your habits and automatically heats the home for you.Clothes have been given an upgrade, too. Electronic thermal jackets, sweaters and coats heat up when you turnthem on. What is the better way to keep warm in the dead of winter? At the touch of a button, or through an app on our phones, the clothing generates heat from elements placed inside. Many models offer three levels of heating which stay warm for over 12 hours.Finally, there is the clothing for the head, Beanies and Earmuffs, that feature speakers included in the fabric using Bluetooth technology so we can listen to our favourite music or, in some cases, have a phone call using the in-built microphone. All while keeping the head warm and avoiding a cold.For many, the thought of winter used to be enough to make their blood run cold. But using technology, life needn’t freeze up. With the right solutions, there’s no reason why winter can’t be really, really cool.12.What do the underlined words “bundle up” mean in Para. 1?A. Fix an air conditioner.B. Take a hot bath.C. Run a lot.D. Put on more clothes.13.How does electronic thermal clothing work?A.The equipment placed inside the clothing produces heat.B.It needs to be warmed up before being used.C.The thermostat heats up automatically when the temperature is low.D.It keeps warm for over 12 hours after being charged for an hour.14.From the passage, we can learn the following statements EXCEPT that .A.Tado’s model can be controlled by saying something to itB.with the in-built speaker and microphone, Beanies and Earmuffs users can have a phone callC.technology can do nothing to make winter less roughD.Bluetooth technology is used in the clothing for the head15.What’s the best title of this passage?A.A Smart ThermostatB.A Modern WinterC.Ways of Keeping WarmD.An Unpleasant Winter第二节(共5 小题；每小题 2.5 分，满分12.5 分)根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

2020年山东省临沂市高考化学一模试卷一、单选题（本大题共14小题，共42.0分）1.下列关于化学与生活的一些说法中不正确的是()A. 卤水点豆腐、明矾净水的原理都是破坏胶体的介稳性B. 铁、铝、铜制容器放置空气中都能在表面形成致密氧化物C. 单晶Ge是半导体，可以作为光电转换材料用于太阳能电池D. 检测酒后驾车者呼出气中的乙醇属于化学检测方法2.用化学用语表示NH3+HCl=NH4Cl中的相关微粒，其中正确的是()A. 中子数为8的氮原子： 78NB. HCl的电子式：C. NH3的结构式：D. Cl−的结构示意图3.下列有关物质的应用说法不正确的是()A. 氢氧化钡可作胃酸的中和剂B. 还原铁粉用作食品抗氧化剂C. Na2O2作漂白剂和供氧剂D. FeCl3溶液能和Cu反应，可用于铜质印刷线路板制作4.设N A表示阿伏加德罗常数的值。

下列说法正确的是()A. 标准状况下，22.4L二氯甲烷中所含共价键的数目为N AB. —定条件下，向密闭容器中充入2molSO2和1molO2，充分反应后，容器中的分子数大于2N AC. 含有4.8g碳原子的石墨晶体中所含共价键的数目为1.2N AD. 将2Ml0.5mol⋅L−1的FeCl3溶液滴入沸水中制备Fe(OH)3胶体，所得胶粒的数目为0.001N A5.任意两个环共用两个不直接相连的碳原子的环烃称为桥环化合物，二环[1.1.0]丁烷()是最简单的一种，下列关于该化合物的说法正确的是()A. 与1−丁烯互为同分异构体B. 二氯代物超过两种C. 所有碳原子均处于同一平面D. 能与2mol H2发生加成反应6.表为元素周期表的一部分，X、Y、Z、R为短周期元素，其中Y元素的原子最外层电子数是其内层电子数的3倍，下列说法正确的是()X YZ′RWA. 原子半径大小关系为：R>Y>XB. X有多种同素异形体，而Y不存在同素异形体C. 根据元素周期律t可以推测W元素的单质具有半导体特性，W2Y3具有氧化性和还原性D. 氢化物熔沸点：H2R>H2Y7.常温下，下列各组离子在指定溶液中一定能大量共存的是()A. 与Al 反应能放H2的溶液中：Cu2+、NH4+、CO32−、SO42−=10−12mol·L−1的溶液中：Mg2+、Fe2+、NO3−、Cl−B. K Wc(OH−)C. 使酚酞变红的溶液中：K+、Na+、I−、AlO2−D. 0.1mol·L−1FeCl3溶液中：Al3+、Ca2+、SCN−、Cl−8.已知反应：2NO(g)+Br2(g)=2NOBr(g)的活化能为a kJ·mol−1，其反应机理如下：①NO(g)+Br2(g)=NOBr2(g)慢；②NO(g)+NOBr2(g)=2NOBr(g)快，下列有关该反应的说法正确的是()A. 反应的速率主要取决于②的快慢B. 反应速率v(NO)=v(NOBr)=2v(Br2)C. NOBr2是该反应的催化剂D. 该反应的焓变等于a kJ·mol−19.下列实验操作能达到实验目的是()A. 稀盐酸可除去烧瓶内残留的MnO2B. 用向上排空气法收集铜粉与稀硝酸反应产生的NOC. 除去NH4Cl溶液中的FeCl3，可向溶液中加入氨水调节pHD. 盛放氯水应用带橡胶塞的细口玻璃瓶10.根据表中信息，判断下列叙述中正确的是()①2B. 氧化性强弱的比较：KClO3>Fe3+>Cl2>Br2C. 表中②组反应的还原产物是KCl，转移6e−D. 表中③组反应的离子方程式为2MnO4−+3H2O2+6H+=2Mn2++4O2↑+6H2O11.Li/Li2O体系的能量循环如图所示。

山东省临沂市2024届高三第二次高考模拟考试语文试题及参考答案一、现代文阅读（35分）（一）现代文阅读I（本题共5小题，18分）阅读下面的文字，完成1～5题。

材料一：除了讲求实用以外，我们还要有一种为学问而学问的兴趣，为真理而真理的态度。

逻辑就它的本身说，是一种纯粹科学。

逻辑之学，自亚里士多德轫创以来，经过中世纪，到九十余年前，一直是在冬眠状态之下。

而自十九世纪中叶波勒等人重新研究以来，突飞猛进，与纯数学合流。

由于晚近逻辑发展之突飞猛进，引起数学对于其本身的种种根本问题之检讨与改进。

写文运思而依照逻辑方式，是一件颇不易办到的事，好比在这个世界上，全然健康的人也不多见。

很少人能说他的运思为文全然无逻辑上的毛病，即使是逻辑专家，也不能完全办到这一点。

逻辑训练，除了积极方面可能助长我们的推论能力以外，在消极方面可以多少防止错误的推论，而且可以直接或间接帮助我们免除种种常见的谬误。

（摘编自殷海光《逻辑新引》）材料二：稻草人谬误是指在论辩过程中通过歪曲对方来反驳对方，或者通过把某种极端荒谬的观点强加给对方来丑化对方的诡辩手法。

就像树起一个稻草人做靶子，并自欺欺人地以为：打倒了这个稻草人，也就打倒了对方。

歪曲对方观点的重要手法有夸张、概括、限制、引申、简化、省略、虚构，等等。

例如，无政府主义者故意把马克思主义的一个重要论点“人们的经济地位决定人们的意识”，歪曲为“吃饭决定思想体系”，并对这个荒谬的论点大加攻击。

有人驳斥了这一偷换论题的诡辩手法：【甲】“究竟何时、何地、在哪个行星上，有哪个马克思说过＇吃饭决定思想体系＇呢？【乙】为什么你们没有从马克思著作中引出一句话或一个字来证实你们的这种论调呢？诚然，马克思说过，人们的经济地位决定人们的意识，决定人们的思想，【丙】可是谁向你们说过吃饭和经济地位是同一种东西呢？难道你们不知道，像吃饭这样的生理现象是与人们的经济地位这种社会现象根本不同的吗？【丁】如果说人们的经济地位等同于吃饭，那么有钱人就不买书不看报只是当个饭桶喽？”稻草人谬误的另一种表现形式是避强就弱、避重就轻、避实就虚，即论敌本来为自己的观点提出了很多论据，在反驳时，却避开对方所提出的那些强有力的、重要的、实实在在的论据，而专挑那些比较弱的、不太重要的、虚的论据展开反击。

山东省临沂市历史高考模拟试卷与参考答案一、单项选择题（本大题有16小题，每小题3分，共48分）1、20世纪初，中国史学界萌生了“疑古”思潮。

胡适提出：“以现在考古学的程度看来，我们对于东周以前的中国古史，只可存一个怀疑的态度。

”由此，“夏王朝否定说”盛行。

1959年二里头遗址的发现为夏的历史提供了可靠的证据，向“东周以上无信史”提出挑战。

对此解读合理的是A. 史学界的疑古思潮完全是错误的B. 文献史料是历史解读的必要依据C. 文献资料必须与实物资料相印证答案：C解析：根据材料“二里头遗址的发现对20世纪初中国史学界的‘东周以上无信史’的观点提出挑战，说明实物史料对于史学研究具有重要的价值”可知，二里头遗址的发现说明实物史料对于史学研究具有重要的价值，即文献资料必须与实物资料相印证，故C项正确；“完全是错误”的说法过于夸张绝对，排除A项；材料内容没有体现文献史料的价值和影响，排除B项。

2、据《汉书·西域传》记载，从敦煌西至盐泽（今新疆罗布泊）都设立了驿亭，在轮台、渠犁（今新疆库尔勒）均有田卒数百人，由使者校尉领护。

汉朝实行的屯田实边制度A. 是中国最早的屯田制B. 具有军政合一特点C. 旨在巩固扩大统一答案：C解析：根据材料“汉朝为了加强对西域地区管理，实行屯田制度”可知，汉朝实行的屯田实边制度是为了加强对西域地区的管理，其目的在于巩固扩大统一，故C 项正确；A项错在“最早”，排除A项；军政合一在材料中无法体现，排除B项。

3、南北朝时期，金属货币在北方几乎绝迹，谷帛代替了钱币作为交易媒介。

但在南方，金属货币的使用却是不断扩大，还产生筹码不足和钱币盗铸等问题。

这反映出当时A. 南方经济水平高于北方B. 南北方商品经济发展程度不同C. 明朝答案：B解析：根据图示内容可以看出，这一时期的宰相籍贯多集中在长江以南，说明南方的教育文化发展水平较高，教育水平高又是经济发展繁荣带来的结果，据此可推知南方成为我国的经济重心，因此应该是南宋时期，但材料强调的是南北方商品经济发展程度不同，而非南方经济水平高于北方，故B项正确，A项错误；明朝时期已经废除了宰相制度，排除C项。

2020年山东省临沂市高考数学一模试卷（理科）一、选择题：本大题共10小题，每小题5分，共50分.在每小题给出的四个选项中，只有一个是符合题目要求的.1．复数z为纯虚数，若（3﹣i）z=a+i（i为虚数单位），则实数a的值为（）A．﹣3 B．3 C．﹣D．2．已知集合A={y|y=（）x，x≥﹣1}，B={y|y=e x+1，x≤0}，则下列结论正确的是（）A．A=B B．A∪B=R C．A∩（∁R B）=∅ D．B∩（∁R A）=∅3．某防疫站对学生进行身体健康调查，欲采用分层抽样的办法抽取样本．某中学生共有学生2000名，抽取了一个容量为200的样本，样本中男生103人，则该中学生共有女生（）A．1030人B．97人C．950人D．970人4．设，且⊥，则向量的夹角为（）A．30°B．60°C．120°D．150°5．下列四个结论中正确的个数是（）①“x2+x﹣2＞0”是“x＞1”的充分不必要条件②命题：“∀x∈R，sinx≤1”的否定是“∃x0∈R，sinx0＞1”．③“若x=，则tanx=1，”的逆命题为真命题；④若f（x）是R上的奇函数，则f（log32）+f（log23）=0．A．1 B．2 C．3 D．46．若执行如图的程序框图，输出S的值为﹣4，则判断框中应填入的条件是（）A．k＜14 B．k＜15 C．k＜16 D．k＜177．在△ABC中，cosA=，3sinB=2sinC，且△ABC的面积为2，则边BC的长为（）A．2 B．3 C．2 D．8．已知a是常数，函数的导函数y=f′（x）的图象如图所示，则函数g（x）=|a x﹣2|的图象可能是（）A．B．C．D．9．若x，y满足不等式组，则z=|x﹣3|+2y的最小值为（）A．4 B．C．6 D．710．设双曲线=1（a＞0，b＞0）的两条渐近线分别l1，l2，右焦点F．若点F关于直线l1的对称点M在l2上则双曲线的离心率为（）A．3 B．2 C．D．二、填空题：本大题共5小题，每小题5分，共25分.把答案填在答题卡对应题号的位置位置.答错位置，书写不清，模棱两可均不得分.11．若tanα=2，则sin2α=_______．12．若f（x）=3﹣2x，则|f（x+1）+2|≤3的解集为_______．13．已知的展开（1﹣2x）5式中所有项的系数和为m，则_______．14．在三棱柱ABC﹣A1B1C1中，侧棱AA1⊥平面AB1C1，AA1=1，底面△ABC是边长为2的正三角形，则此三棱柱的体积为_______．15．已知实数x，y满足x＞y＞0且x+y=1，则+的最小值是_______．三、解答题：本大题共6小题，共70分.解答应写出文字说明，证明过程或演算步骤.把答案填在答题卡上的相应位置.16．已知函数满足下列条件：•①周期T=π；②‚图象向左平移个单位长度后关于y轴对称；③ƒf（0）=1．（Ⅰ）求函数f（x）的解析式；（Ⅱ）设，求cos（2α﹣2β）的值．17．如图，在四棱锥P﹣ABCD中，底面ABCD为菱形，M，N分别为PB，CD的中点，二面角P﹣CD﹣A的大小为60°，∠ABC=60°，AB=2，PC=PD=（Ⅰ）求证：PA⊥平面ABCD；（Ⅱ）求直线MN与平面PCD所成角的正弦值．18．已知正项数列{a n}的前n项和S n满足6S n=a n2+3a n+2，且a2是a1和a6的等比中项．（Ⅰ）求数列{a n}的通项公式；（Ⅱ）符合[x]表示不超过实数x的最大整数，如[log23]=1，[log25]=2．记，求数列的前n项和T n．19．a，b，c，d四名运动员争夺某次赛事的第1，2，3，4名，比赛规则为：通过抽签，将4人分为甲、乙两个小组，每组两人．第一轮比赛（半决赛）：两组各自在组内进行一场比赛，决出各组的胜者和负者；第二轮比赛决赛：两组中的胜者进行一场比赛争夺1，2名，两组中的负者进行一场比赛争夺第3，4名．四名选手以往交手的胜负情况累计如下表：a b c da a13胜26负a20胜10负a21胜21负b b26胜13负b14胜28负b19胜19负c c10胜20负c28胜14负c18胜18负d d21胜21负d19胜19负d18胜18负若抽签结果为甲组：a，c；乙组：b，d．每场比赛中，双方以往交手各自获胜的频率作为获胜的概率．（Ⅰ）求c获得第1名的概率；（Ⅱ）求c的名次X的分布列和数学期望．20．已知函数f（x）=x2﹣2ax，g（x）=lnx．（Ⅰ）若f（x）≥g（x）对于定义域内的任意x恒成立，求实数a的取值范围；（Ⅱ）设h（x）=f（x）+g（x）有两个极值点x1，x2且，证明：h（x1）﹣h （x2）＞﹣ln2．21．已知椭圆C1：=1（a＞b＞0）的离心率为，其短轴的下端点在抛物线x2=4y 的准线上．（Ⅰ）求椭圆C1的方程；（Ⅱ）设O为坐标原点，M是直线l：x=2上的动点，F为椭圆的右焦点，过点F作OM的垂线与以为OM直径的圆C2相交于P，Q两点，与椭圆C1相交于A，B两点，如图所示．•①若PQ=，求圆C2的方程；②‚设C2与四边形OAMB的面积分别为S1，S2，若S1=λS2，求λ的取值范围．2020年山东省临沂市高考数学一模试卷（理科）参考答案与试题解析一、选择题：本大题共10小题，每小题5分，共50分.在每小题给出的四个选项中，只有一个是符合题目要求的.1．复数z为纯虚数，若（3﹣i）z=a+i（i为虚数单位），则实数a的值为（）A．﹣3 B．3 C．﹣D．【考点】复数相等的充要条件．【分析】设出复数z，然后利用复数相等的充要条件，求解即可．【解答】解：设复数z=bi，b≠0，∴（3﹣i）z=a+i，化为（3﹣i）bi=a+i，即b+3bi=a+i，∴b=a=，故选：D．2．已知集合A={y|y=（）x，x≥﹣1}，B={y|y=e x+1，x≤0}，则下列结论正确的是（）A．A=B B．A∪B=R C．A∩（∁R B）=∅ D．B∩（∁R A）=∅【考点】交、并、补集的混合运算．【分析】化简集合A、B，求出∁R A，即可得出结论．【解答】解：集合A={y|y=（）x，x≥﹣1}={y|0＜y≤2}=（0，2]，B={y|y=e x+1，x≤0}={y|1＜y≤2}=（1，2]，∴∁R A=（﹣∞，0]∪（2，+∞），∴B∩（∁R A）=∅．故选：D．3．某防疫站对学生进行身体健康调查，欲采用分层抽样的办法抽取样本．某中学生共有学生2000名，抽取了一个容量为200的样本，样本中男生103人，则该中学生共有女生（）A．1030人B．97人C．950人D．970人【考点】分层抽样方法．【分析】根据样本容量和女生比男生少6人，可得样本中女生数，再根据抽取的比例可得总体中的女生人数．【解答】解：∵样本容量为200，女生比男生少6人，∴样本中女生数为97人，又分层抽样的抽取比例为=，∴总体中女生数为970人．故选：D．4．设，且⊥，则向量的夹角为（）A．30°B．60°C．120°D．150°【考点】数量积表示两个向量的夹角．【分析】⊥，可得=0，解得x．再利用向量夹角公式即可得出．【解答】解：∵⊥，∴=x﹣3=0，解得x=．∴=（0，4），∴（）•=﹣12，||=4，==2，设向量的夹角为θ，∴cosθ===﹣，∴θ=150°．故选：D．5．下列四个结论中正确的个数是（）①“x2+x﹣2＞0”是“x＞1”的充分不必要条件②命题：“∀x∈R，sinx≤1”的否定是“∃x0∈R，sinx0＞1”．③“若x=，则tanx=1，”的逆命题为真命题；④若f（x）是R上的奇函数，则f（log32）+f（log23）=0．A．1 B．2 C．3 D．4【考点】四种命题．【分析】①由充分必要条件的定义，即可判断；②由含有一个量词的命题的否定形式，即可判断；③先求出逆命题，再判断真假即可，④根据奇函数的性质和对数的运算法则即可判断．【解答】解：对于①，x2+x﹣2＞0，解得x＜﹣2或x＞1，故“x＞1”的必要不充分条件，故错误，对于②，命题：“∀x∈R，sinx≤1”的否定是“∃x0∈R，sinx0＞1”，故正确，对于③，若x=，则tanx=1，”的逆命题为“若tanx=1，则x=，x还可以等于，故错误，对于④，f（x）是R上的奇函数，则f（﹣x）=﹣f（x），∵log32=，∴log32与log23不是互为相反数，故错误．故选：A．6．若执行如图的程序框图，输出S的值为﹣4，则判断框中应填入的条件是（）A．k＜14 B．k＜15 C．k＜16 D．k＜17【考点】程序框图．【分析】根据程序框图，写出运行结果，根据程序输出的结果是S=﹣4，可得出判断框内应填入的条件．【解答】解：执行如图的程序框图，运行结果如下：第1次循环S=log2=﹣1，k=2；第2次循环S=log2+log2=log2，k=3；第3次循环S=log2+log2=log2=﹣2，k=4；第4次循环S=log23+log2=log2，k=5；第5次循环S=log2+log2=log2，k=6；第6次循环S=log2+log2=log2，k=7；第7次循环S=log2+log24=log2=﹣3，k=8；…第14次循环S=log2+log2=log2，k=15；第15次循环S=log2+log2=log2=﹣4，•k=16；如果输出S=﹣4，那么只能进行15次循环，故判断框内应填入的条件是k＜16．故选：C．7．在△ABC中，cosA=，3sinB=2sinC，且△ABC的面积为2，则边BC的长为（）A．2 B．3 C．2 D．【考点】正弦定理；余弦定理．【分析】由cosA=，A∈（0，π），可得sinA=．由3sinB=2sinC，且△ABC 的面积为2，可得3b=2c，=2，再利用余弦定理可得：a2=b2+c2﹣2bccosA．【解答】解：∵cosA=，A∈（0，π），∴sinA==，∵3sinB=2sinC，且△ABC的面积为2，∴3b=2c，=2，解得b=2，c=3．∴a2=b2+c2﹣2bccosA=22+32﹣2×2×3×=9，解得a=3．故选：B．8．已知a是常数，函数的导函数y=f′（x）的图象如图所示，则函数g（x）=|a x﹣2|的图象可能是（）A．B．C．D．【考点】指数函数的图象变换．【分析】求出原函数的导函数，由导函数的图象得到a＞1，然后利用指数函数的图象平移得答案．【解答】解：∵，∴f′（x）=x2+（1﹣a）x﹣a，由函数y=f′（x）的图象可知，∴a＞1，则函数g（x）=|a x﹣2|的图象是把函数y=a x向下平移2个单位，然后取绝对值得到，如图．故可能是D．故选：D．9．若x，y满足不等式组，则z=|x﹣3|+2y的最小值为（）A．4 B．C．6 D．7【考点】简单线性规划．【分析】由题意作出其平面区域，化简z=|x﹣3|+2y=，从而分别求最小值，从而解得．【解答】解：由题意作出其平面区域如右图，易知A（0，2），B（5，3），C（3，5），D（3，）；z=|x﹣3|+2y=，当x≥3时，z=x+2y﹣3在点D处取得最小值为，当x＜3时，z=﹣x+2y+3＞，故z=|x﹣3|+2y的最小值为，故选B．10．设双曲线=1（a＞0，b＞0）的两条渐近线分别l1，l2，右焦点F．若点F关于直线l1的对称点M在l2上则双曲线的离心率为（）A．3 B．2 C．D．【考点】双曲线的简单性质．【分析】不妨设l1为y=x，l2为y=﹣x，设出对称点的坐标，根据中点坐标公式和斜率公式即可求出a与b的关系，再根据离心率公式即可求出．【解答】解：l1，l2分别为双曲线=1（a＞0，b＞0）的两条渐近线，不妨设l1为y=x，l2为y=﹣x，由右焦点关于l1的对称点l2在上，设右焦点F关于l1的对称点为M（m，﹣），右焦点F坐标为（c，0），MF中点坐标为（，﹣），可得﹣=•，解得m=﹣c，即有M（﹣c，），可得MF的斜率为=﹣，即有﹣•=﹣1，可得b2=3a2，即c2=a2+b2=4a2，则c=2a，可得e==2，故选：B．二、填空题：本大题共5小题，每小题5分，共25分.把答案填在答题卡对应题号的位置位置.答错位置，书写不清，模棱两可均不得分.11．若tanα=2，则sin2α=．【考点】二倍角的正弦；同角三角函数间的基本关系．【分析】利用同角三角函数的基本关系以及二倍角的正弦公式，把要求的式子化为，把已知条件代入运算求得结果．【解答】解：∵tanα=2，∴sin2α=2sinαcosα===，故答案为．12．若f（x）=3﹣2x，则|f（x+1）+2|≤3的解集为[0，3] ．【考点】绝对值不等式的解法．【分析】求出f（x+1），问题转化为：|2x﹣3|≤3，解出即可．【解答】解：若f（x）=3﹣2x，则|f（x+1）+2|=|3﹣2（x+1）+2|=|2x﹣3|≤3，解得：0≤x≤3，故不等式的解集为[0，3]，故答案为：[0，3]．13．已知的展开（1﹣2x）5式中所有项的系数和为m，则ln2．【考点】二项式系数的性质．【分析】根据展开式中所有项的系数和求出m的值，再计算定积分的值即可．【解答】解：展开（1﹣2x）5式中所有项的系数和为m=（1﹣2）5=﹣1，∴x﹣1dx=lnx=ln2﹣ln1=ln2．故答案为：ln2．14．在三棱柱ABC﹣A1B1C1中，侧棱AA1⊥平面AB1C1，AA1=1，底面△ABC是边长为2的正三角形，则此三棱柱的体积为．【考点】棱柱、棱锥、棱台的体积．【分析】由等积法证明，然后利用棱锥的体积公式求得答案．【解答】解：如图，连接B1C，则，又，∴，∵AA1⊥平面AB1C1，AA1=1，底面△ABC是边长为2的正三角形，∴．15．已知实数x，y满足x＞y＞0且x+y=1，则+的最小值是．【考点】基本不等式．【分析】化简+=+=2++，从而利用基本不等式求解．【解答】解： +=+=2+2++=2++≥2+=，（当且仅当2=，即x=，y=时，等号成立），故答案为：．三、解答题：本大题共6小题，共70分.解答应写出文字说明，证明过程或演算步骤.把答案填在答题卡上的相应位置.16．已知函数满足下列条件：•①周期T=π；②‚图象向左平移个单位长度后关于y轴对称；③ƒf（0）=1．（Ⅰ）求函数f（x）的解析式；（Ⅱ）设，求cos（2α﹣2β）的值．【考点】由y=Asin（ωx+φ）的部分图象确定其解析式；函数y=Asin（ωx+φ）的图象变换．【分析】（Ⅰ）根据f（x）的周期求出ω的值，根据f（x）的图象平移以及g（x）的图象关于y轴对称，求出φ的值，再由f（0）=1求出A的值，即得f（x）的解析式；（Ⅱ）根据f（α﹣）与f（β+）的值求出cos2α、cos2β，再根据α、β的范围求出sin2α、sin2β，从而求出cos（2α﹣2β）的值．【解答】解：（Ⅰ）∵f（x）的周期为T==π，∴ω=2；又函数f（x）的图象向左平移个单位长度，变为g（x）=Asin[2（x+）+φ]，由题意，g（x）的图象关于y轴对称，∴2×+φ=+kπ，k∈Z；又|φ|＜，∴φ=，∴函数f（x）=Asin（2x+）；又f（0）=1，∴Asin=1，解得A=2，∴函数f（x）=2sin（2x+）；（Ⅱ）由f（α﹣）=﹣，f（β+）=，得2sin（2α﹣+）=﹣，2sin（2β++）=，∴cos2α=，cos2β=；又α、β∈（0，），∴2α、2β∈（0，），∴sin2α=，sin2β=，∴cos（2α﹣2β）=cos2αcos2β+sin2αsin2β=×+×=．17．如图，在四棱锥P﹣ABCD中，底面ABCD为菱形，M，N分别为PB，CD的中点，二面角P﹣CD﹣A的大小为60°，∠ABC=60°，AB=2，PC=PD=（Ⅰ）求证：PA⊥平面ABCD；（Ⅱ）求直线MN与平面PCD所成角的正弦值．【考点】直线与平面所成的角；直线与平面垂直的判定．【分析】（I）连结AN，根据三线合一可得AN⊥CD，PN⊥CD，于是得出CD⊥平面PAN，故而PA⊥CD，计算AN，PN，利用余弦定理求出PA，得出PA⊥AN，从而得出PA⊥平面ABCD；（II）以A为原点建立空间坐标系，求出平面PCD的法向量，则|cos＜，＞|即为所求．【解答】证明：（I）连结AN，∵四边形ABCD是菱形，∠ABC=60°，∴△ACD是等边三角形，∵N是CD的中点，PC=PD，∴AN⊥CD，PN⊥CD，∴∠PNA为二面角P﹣CD﹣A的平面角，且CD⊥平面PAN．∴PA⊥CD，∠PNA=60°．∵AB=AD=2，PC=PD=．∴AN=，PN==2．在△PAN中，由余弦定理得PA2=AN2+PN2﹣2AN•PNcos60°=3+12﹣2=9．∴PA2+AN2=PN2，∴PA⊥AN，又CD⊂平面ABCD，AN⊂平面ABCD，AN∩CD=N，∴PA⊥平面ABCD．（II）以A为原点，以AB，AN，AP为坐标轴建立空间直角坐标系，如图所示：则A（0，0，0），B（2，0，0），N（0，，0），P（0，0，3），C（1，，0），D（﹣1，，0）．∴M（1，0，）．∴=（﹣1，，﹣），=（1，，﹣3），=（﹣2，0，0）．设平面PCD的法向量为=（x，y，z），则，=0，∴，令z=1得=（0，，1）．∴=，∴cos＜＞===．∴直线MN与平面PCD所成角的正弦值为．18．已知正项数列{a n }的前n 项和S n 满足6S n =a n 2+3a n +2，且a 2是a 1和a 6的等比中项． （Ⅰ）求数列{a n }的通项公式；（Ⅱ）符合[x ]表示不超过实数x 的最大整数，如[log 23]=1，[log 25]=2．记，求数列的前n 项和T n ．【考点】数列的求和；等比数列的通项公式． 【分析】（I ）由6S n =a n 2+3a n +2，当n ≥2时，+2，可得：6a n =﹣+3a n ﹣3a n ﹣1，化为（a n +a n ﹣1）（a n ﹣a n ﹣1﹣3）=0，根据数列{a n }是正项数列，及其等差数列的通项公式、a 2是a 1和a 6的等比中项即可得出． （II ）=[log 2（n +1）]，可得==n ，=n •2n ．利用“错位相减法”与等比数列的前n 项和公式即可得出． 【解答】解：（I ）由6S n =a n 2+3a n +2，当n ≥2时， +2，可得：6a n =﹣+3a n ﹣3a n ﹣1，化为（a n +a n ﹣1）（a n ﹣a n ﹣1﹣3）=0，∵数列{a n }是正项数列，∴a n +a n ﹣1＞0，可得a n ﹣a n ﹣1=3， ∴数列{a n }是等差数列，公差为3． 由6a 1=+3a 1+2，解得a 1=1或2．当a 1=2时，a n =2+3（n ﹣1）=3n ﹣1，可得a 2=5，a 6=17，不满足a 2是a 1和a 6的等比中项，舍去．当a 1=1时，a n =1+3（n ﹣1）=3n ﹣2，可得a 2=4，a 6=16，满足a 2是a 1和a 6的等比中项． ∴a n =3n ﹣2． （II ）=[log 2（n +1）]，∴==n ，∴=n •2n ．∴数列的前n 项和T n =2+2×22+3×23+…+n •2n ，2T n =22+2×23+…+（n ﹣1）•2n +n •2n+1，∴﹣T n=2+22+…+2n﹣n•2n+1=2×﹣n•2n+1=（1﹣n）•2n+1﹣2，∴T n=（n﹣1）•2n+1+2．19．a，b，c，d四名运动员争夺某次赛事的第1，2，3，4名，比赛规则为：通过抽签，将4人分为甲、乙两个小组，每组两人．第一轮比赛（半决赛）：两组各自在组内进行一场比赛，决出各组的胜者和负者；第二轮比赛决赛：两组中的胜者进行一场比赛争夺1，2名，两组中的负者进行一场比赛争夺第3，4名．四名选手以往交手的胜负情况累计如下表：a b c da a13胜26负a20胜10负a21胜21负b b26胜13负b14胜28负b19胜19负c c10胜20负c28胜14负c18胜18负d d21胜21负d19胜19负d18胜18负若抽签结果为甲组：a，c；乙组：b，d．每场比赛中，双方以往交手各自获胜的频率作为获胜的概率．（Ⅰ）求c获得第1名的概率；（Ⅱ）求c的名次X的分布列和数学期望．【考点】离散型随机变量的期望与方差；离散型随机变量及其分布列．【分析】（Ⅰ）求出a分别与b，c，d比赛时获胜的概率，b分别与a，c，d比赛时获胜的概率，c分别与a，b，d比赛时获胜的概率，由此能求出C获得第一名的概率．（Ⅱ）C名次X的可能取值有1，2，3，4，分别求出相应的概率，由此能求出X的分布列和EX．【解答】解：（Ⅰ）设a分别与b，c，d比赛时获胜的事件分别为A b，A c，A d，则P（A b）=，P（A c）=，P（A d）=，b分别与a，c，d比赛时获胜的事件分别为B a，B c，B d，则P（B a）=，P（B c）=，P（B d）=，c分别与a，b，d比赛时获胜的事件分别为C a，C b，C d，则P（C a）=，P（C b）=，P（C d）=，d分别与a，b，c比赛时获胜的事件分别为Da，D b，D c，则P（D a）=，P（D b）=，P（D c）=，∴C获得第一名的概率：P=P（C a）P（B d）P（C b）+P（C a）P（D b）P（C d）==．（Ⅱ）C名次X的可能取值有1，2，3，4，P（X=1）=P（C a）P（B d）P（C b）+P（C a）P（D b）P（C d）==．若C为第二名，则甲组中C胜，且C与乙组的胜者比赛时负，∴P（X=2）=P（C a）P（B d）P（B c）+P（C a）P（D b）P（D c）==，若C为第3名，则甲组中C负，且C与乙组的负者比赛时胜，∴P（X=3）=P（A c）P（D b）P（C b）+P（A c）P（B d）P（C d）═+=，P（X=4）=1﹣P（X=1）﹣P（X=2）﹣P（X=3）=1﹣=．∴X的分布列为：X 1 2 3 4PEX==．20．已知函数f（x）=x2﹣2ax，g（x）=lnx．（Ⅰ）若f（x）≥g（x）对于定义域内的任意x恒成立，求实数a的取值范围；（Ⅱ）设h（x）=f（x）+g（x）有两个极值点x1，x2且，证明：h（x1）﹣h （x2）＞﹣ln2．【考点】利用导数求闭区间上函数的最值；利用导数研究函数的单调性．【分析】（Ⅰ）分离参数a可得：a≤（x﹣），（x＞0），设ω（x）=（x﹣），根据函数的单调性求出函数的最小值，从而求出a的范围即可；（Ⅱ）求出h（x）的导数，得到x2=∈（1，+∞），且2ax1=2+1，2ax2=2+1，设μ（x）=x2﹣﹣ln2x2（x＞1），求出函数的单调性，证出结论即可．【解答】解：（Ⅰ）由题意得：f（x）≥g（x）⇔x2﹣2ax≥lnx，（x＞0），分离参数a可得：a≤（x﹣），（x＞0），设ω（x）=（x﹣），则ω′（x）=，由于y=x2，y=lnx在（0，+∞）递增，∴y=x2+lnx﹣1在（0，+∞）递增，显然x=1时，该函数值是0，x∈（0，1）时，ω′（x）＜0，x∈（1，+∞）时，ω′（x）＞0，∴ω（x）min=ω（1）=，∴a≤ω（x）min=，即a∈（﹣∞，]．（Ⅱ）证明：由题意得：h（x）=x2﹣2ax+lnx，则h′（x）=2x﹣2a+=（x＞0），∴方程2x2﹣2ax+1=0（x＞0）有2个不相等的实数根x1，x2且x1∈（0，），又∵x1 x2=，∴x2=∈（1，+∞），且2ax1=2+1，2ax2=2+1，而h（x1）﹣h（x2）=[﹣（2+1）+lnx1]﹣[﹣（2+1）+lnx2]=﹣﹣ln2，（x2＞1），设μ（x）=x2﹣﹣ln2x2（x＞1），令t=x2，则t＞1，μ（t）=t﹣﹣ln2t，∴μ′（t）=1+﹣=≥0，∴μ（t）＞μ（1）=1﹣﹣ln2=﹣ln2，即h（x1）﹣h（x2）＞﹣ln2．21．已知椭圆C1：=1（a＞b＞0）的离心率为，其短轴的下端点在抛物线x2=4y的准线上．（Ⅰ）求椭圆C1的方程；（Ⅱ）设O为坐标原点，M是直线l：x=2上的动点，F为椭圆的右焦点，过点F作OM的垂线与以为OM直径的圆C2相交于P，Q两点，与椭圆C1相交于A，B两点，如图所示．•①若PQ=，求圆C2的方程；②‚设C2与四边形OAMB的面积分别为S1，S2，若S1=λS2，求λ的取值范围．【考点】椭圆的简单性质．【分析】（Ⅰ）由椭圆离心率为，其短轴的下端点在抛物线x2=4y的准线上，列出方程组求出a，b，由此能求出椭圆C1的方程．（Ⅱ）①设M（2，t），则C2的方程为（x﹣1）2+（y﹣）2=1+，由此利用圆的性质结合已知条件能求出圆C2的方程．②由①知PQ方程为2x+ty﹣2=0，（t≠0），代入椭圆方程得（8+t2）x2﹣16x+8﹣2t2=0，t ≠0，由此利用根的判断式、韦达定理、弦长公式、分类讨论思想，能求出λ的取值范围．【解答】解：（Ⅰ）∵椭圆C1：=1（a＞b＞0）的离心率为，其短轴的下端点在抛物线x2=4y的准线上，∴，解得a=，b=c=1，∴椭圆C1的方程为．（Ⅱ）①由（Ⅰ）知F（1，0），设M（2，t），则C2的圆心坐标为（1，），C2的方程为（x﹣1）2+（y﹣）2=1+，直线PQ方程为y=（x﹣1），（t≠0），即2x+ty﹣2=0，（t≠0）又圆C2的半径r==，由（）2+d2=r2，得（）2+=，解得t2=4，∴t=±2，∴圆C2的方程为：（x﹣1）2+（y﹣1）2=2或（x﹣1）2+（y+1）2=2．②由①知PQ方程为2x+ty﹣2=0，（t≠0），由，得（8+t2）x2﹣16x+8﹣2t2=0，t≠0，则△=（﹣16）2﹣4（8+t2）（8﹣2t2）=8（t4+4t2）＞0，，，|AB|===2×，∴==，S1=πr2=，∵S1=λS2，∴==，当t=0时，PQ的方程为x=1，|AB|=，|OM|=2，|OM|×|AB|=，=π，∴．∵S1=λS2，∴====＞=．当直线PQ的斜率不存在时，PQ方程为x=1，|AB|=，|OM|=2，∴S2=|OM|×|AB|=，S1==π，．综上，．2020年9月12日。