2
3<+<
n n
，即44233+<<+n n n
，解得4=n ，…………8分
所以5
16=d ．所以所得等差数列首项为16，公差为3
16，共有6项．………………10分
所以这个等差数列所有项的和T 1442
)
3216(6=+?=
． ………………11分
所以，4=n ，144=T ． ………………12分
（3）由（1）知n n f 2)(=，所以)log (2
m n f n c n ??=2
22
log log
2
2
m
n m
n n n ???=?=
n
n
m
m
n m
n n n 22log log 2)
2
(2
22?=?=?=?．………………14分
由题意，n n c c <+1，即n n m n m n 222)1(?
2+<
n n m 1
11+-=n 对任意*N ∈n 成立．………………16分
因为1
11)(+-
=n n g 在*N ∈n 上是单调递增的，所以)(n g 的最小值为2
1)1(=g ．
所以21
2
m 得m 的取值范围是???
? ??22,0． 所以，当???
?
??∈22,0m 时，数列}{n c 是单调递减数列． ………………18分
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2020届上海高三英语二模汇编 语法填空
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