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2017-2018学年高中地理 水资源的合理利用双基限时练 新人教版必修1

2017-2018学年高中地理 水资源的合理利用双基限时练 新人教版必修1
2017-2018学年高中地理 水资源的合理利用双基限时练 新人教版必修1

水资源的合理利用

一、单项选择题

1.下列关于水资源的叙述,正确的是( )

A.通常所说的水资源是指陆地上所有的水

B.海洋水是地球上最主要的水资源

C.冰川是地球上水的主体

D.河流、淡水湖泊、浅层地下水是目前利用的主要水资源

答案 D

2.有关水资源地区分布的叙述中正确的是( )

A.总量南美洲>亚洲B.总量大洋洲>欧洲

C.人均巴西>印度D.人均中国>美国

答案 C

3.下列叙述符合我国水资源时空分布特征的是( )

A.夏秋多,北方多 B.冬春多,东部多

C.夏秋少,南部少 D.冬春少,西部少

答案 D

4.目前,我国水资源最短缺的地区主要位于( )

A.干旱区B.半干旱区

C.半湿润区D.湿润区

解析目前,我国水资源最短缺的地区是华北平原,而华北平原属于半湿润地区,所以本题选C。

答案 C

千岛湖为国家一级水资源保护区,面积为580平方千米。农夫山泉源出于千岛湖距南山3.5千米处深层,常年水温12℃,天然清纯,味道甘洌,水中富含钙、钠、镁、钾、偏硅酸等。“农夫山泉有点甜”一句脍炙人口的广告语使“农夫山泉饮用天然水”享誉国内外。据此完成5~6题。

5.“农夫山泉饮用天然水”属于下列水资源中的( )

A.淡水湖泊水B.浅层地下水

C.河流水D.深层地下水

6.“农夫山泉饮用天然水”能够享誉国内外的原因是( )

A.数量巨大,易开采B.开发利用历史悠久

C.质量高,饮用安全D.农夫山泉为天然水

5~6.解析文字材料的阅读过程中,能否敏锐地察觉关键信息,直接关系到解题的速度和准确率,上述材料中的“3.5千米”和山泉水特征的描述即为关键信息。

答案 5.D 6.C

联合国确定的2013年世界水日的宣传主题是“水合作”,我国2013年世界水日和中国水周活动的宣传主题是“节约保护水资源,大力建设生态文明”。结合相关知识回答7~8题。

7.有关我国水资源时空变化特点的叙述,正确的是( )

A.时空分布不均,南方多,北方少;东部少,西部多

B.西北地区远离海洋,降水稀少,没有河流分布

C.我国春夏降水多,水资源较丰富;秋冬降水少,水资源较贫乏

D.华北地区是我国水资源短缺严重的地区之一,春季的供需矛盾最突出

8.下列叙述属于节约保护水资源措施的是( )

①跨流域调水②发展滴灌、喷灌技术③实施阶梯水价④海水淡化⑤建立和完善水资源监控系统⑥寻找地表水替代水源

A.①③⑥ B.②③⑤

C.①②④ D.④⑤⑥

7~8.解析第7题,华北地区冬春两季降水少,春季气温回升快,水资源贫乏;春季农业用水迅速增加,水资源供需矛盾最突出。第8题,跨流域调水、海水淡化和寻找地表水替代水源等措施属于开发新的水源,不属于节约保护水资源的措施。

答案7.D 8.B

下图是北半球内陆某区域图,据图判断9~10题。

9.图中湖泊的最大水量一般出现在( )

A.冬季 B.秋季

C.春季 D.夏季

解析由题干中的空间位置信息,结合图例来判断,图中湖泊为内流湖,其补给水源为高山冰雪融水,夏天气温高、冰雪消融量大,湖泊水量丰富。

答案 D

10.近些年来该湖泊面积逐年萎缩。对这一现象的原因推测中,最不可能成立的是( ) A.人口增长迅速

B.气候异常,蒸发量增大

C.湖泊对地下水补给量增大,即渗漏严重

D.为争取增产粮食,开荒种地

解析湖泊萎缩主要与人类活动有关,如果人类过量用水,会导致地下水位下降,湖泊对地下水补给量将增大。

答案 B

读中国某气象灾害多发原因示意图,回答11~12题。

11.该地区最可能是我国的( )

A.东北地区 B.华北地区

C.西北地区 D.西南地区

答案 B

12.研究表明,该地区冬季降水比春季少,但春季干旱程度更高,其原因不可能是( ) A.春季气温回升,蒸发量大

B.农业灌溉用水量较大

C.春季多大风天气,蒸发量旺盛

D.人口、城市密集,人均水资源匮乏

答案 D

济平干渠工程位于山东济南至东平湖之间,输水线路全长90.055千米,是南水北调东线一期工程的骨干工程之一,也是向胶东输水的首段工程。据此回答13~14题。

13.济平干渠在沿线地区实施防渗衬砌措施,首次实现了大块塑薄混凝土板在渠道衬砌中应用,渠道衬砌的主要目的是( )

A.防止水渗漏损失,提高渠水利用效率和输水效率

B.防止沿途某些地区的水土流失

C.减少地表径流

D.改善其航运条件

14.济平干渠的建成,对沿线地区的有利影响是( )

A.向东营市区及沿途县区补充城镇生活和工业用水

B.缓解沿线地区能源紧张状况

C.减少沿线地区的水污染

D.有效缓解济南市的供水危机,改善生态环境

13~14.解析第13题,渠道防渗可以起到防止漏渗,提高水资源的利用效率,也可以防止沿线地区因地下水位上升而造成的次生盐碱化。第14题,济平干渠引调了东平湖水,向济南市区及沿途县区补充城镇生活和工业用水,改善了沿线的生态环境,下一步将承担着向胶东地区输送长江水的重要任务。

答案13.A 14.D

二、综合题

15.分析下面图表资料,回答问题。

(1)两省区在水资源利用结构上有哪些差异?

(2)简要分析宁夏的农田灌溉亩均用水量比江苏多的自然和人为原因。

(3)若缺水类型包括资源性缺水和水质性缺水,那么江苏省缺水的原因是___________________________________________________

_______________________________________________________________________________ ______________。

答案(1)江苏的生活用水比重比宁夏大,生产用水比重比宁夏小。

(2)自然原因:宁夏的降水量比江苏少得多,而蒸发又比较旺盛;人为原因:灌溉方式不合理,浪费严重。

(3)水质性缺水,江苏省经济发展迅速,水体污染较严重

16.中东地区是世界的热点地区,巴以冲突最难解决。已故约旦国王侯赛因说过:“如果约以之间爆发战争,那么水问题肯定是惟一的原因。”读下表和图,回答下列问题。

(1)图中甲、乙两地分别是________和________。从成因上看,甲是________而形成,乙是由于终年受________控制而形成。

(2)该地区最重要的水源是________,此水源对该地区的重要性是________________________________________________________ ________________。

(3)“水比牛奶贵”的中东以________、灌溉农业为主。为解决水源短缺问题而长期致力于灌溉技术的研究,已成功地把计算机控制技术普及到灌溉系统,达到浇作物而不浇土地。我国________和________地区迫切需要引进这种技术。

答案(1)死海撒哈拉沙漠板块张裂运动(或地壳断裂下陷) 副热带高压带

(2)约旦河该地区气候干旱、淡水缺乏,约旦河是工农业生产和生活用水的主要来源

(3)畜牧业西北华北

人教新课标版语文高一人教版必修三双基限时练 12动物游戏之谜

双基限时练(十二)动物游戏之谜 一、基础测试 1.下列词语中,加点字的注音完全正确的一项是() A.缅.甸(miàn)聒.噪(ɡuō) 潜.游(qián) 嬉.闹(xī) B.脊.背(jǐ) 挨.挤(ái) 倒.立(dào) 消耗.(hào) C.汲.取(jí) 安抚.(fǔ) 尾鳍.(qí) 格.斗(ɡé) D.反馈.(kuì) 模.式(mó) 捉.摸(zuó) 嚼.烂(jiáo) 解析A.缅miǎn;B.挨āi;D.捉zhuō。 答案 C 2.下列词语中,没有错别字的一项是() A.伙伴兴高彩烈平衡史无前例 B.默契得意扬扬厮打销声匿迹 C.跳越猩猩相惜消融铁打金刚 D.元气自娱自乐调剂杂草老藤 解析A.兴高彩.烈—采;B.得意扬扬 ..—洋洋;C.跳越.—跃,猩猩 ..相惜—惺惺。 答案 D 3.下列加点的成语使用不正确的一项是() A.在动物身上,无论从形态结构、生理过程,还是行为方面去分析,尽可能节省能量 的例子几乎俯拾皆是 ....。 B.单独游戏时,动物常常兴高采烈 ....地独自奔跑、跳跃,在原地打圈子。 C.每当刮起大风时,成群的露脊鲸把尾鳍高高举出水面,正对着大风,以便像船帆似 的,让大风推着它们,得意洋洋 ....地“驶”向海岸。 D.研究者们各执己见,众说纷纭 ....。 解析A项中应是“比比皆是”。“比比皆是”和“俯拾皆是”都表示相同的事物很多,到处都是。前者侧重表示多得很,到处都是;后者侧重表示容易得到。 答案 A 4.下列各句没有语病的一句是() A.动物的游戏行为,是动物行为研究中被认为最复杂、最难以捉摸、引起争论最多的

行为。 B.在动物身上,无论从形态结构、生理过程和行为方面去分析,尽可能节省能量的例子比比皆是。 C.地震发生后,当地政府及解放军部队全力救助,目前灾区群众已住进了临时帐篷,防止余震再次发生。 D.有人认为科学家终日埋头科研,不问家事,有点不近人情,然而事实却是对这种偏见的最好说明。 解析B项中应将“和”改为“还是”;C项不合逻辑,应为“预防余震发生”;D项中“事实是说明”正好说反了,依句意应是“事实正是对上述说法的反驳”。 答案 A 5.下列句子中标点符号的使用,不正确的一项是() A.马驹常常欢快地连续扬起前蹄,轻盈地蹦跳;猴类喜欢在地上翻滚,拉着树枝荡秋千……单独游戏时动物显得自由自在。 B.这些科学家认为,动物游戏是为了“自我娱乐”,而自我娱乐是动物天性的表现,正像捕食、逃避敌害,繁殖行为等是动物的天性一样。 C.这几种假说,哪一种更有道理?动物的游戏,究竟是为了“演习”,为了“自娱”,为了“学习”,还是为了“锻炼”?研究者们各执己见,众说纷纭。 D.电视剧《水浒传》标明作者为施耐庵、罗贯中,引起许多观众的疑惑:《水浒传》的作者不是施耐庵吗?怎么又多出个罗贯中? 解析B项中,第二个“自我娱乐”也应加引号,“逃避敌害”后的逗号应改为顿号,因为三者处在同一等级的并列上。 答案 B 6.下列语句排列正确的一项是() ①否则,我就只能相信,这些曲调是真正的音乐。 ②那些歌也许是有关航行,或有关浮游节肢动物的来源,或有关领地界限的简单而实打实的叙述和声明。 ③当然还有其他方法来解释鲸鱼之歌。 ④除非有一天有人证明,这些长长的、缭绕的、执著的曲调,被不同的歌唱者重复着,又加上了它们各自的修饰,这不过是为了向海面下数百英里之外传递像“鲸鱼在这儿”之类寻常的信息。 ⑤但迄今证据还没有得到。 A.③①②⑤④B.②③①④⑤ C.⑤②③①④D.③②⑤④① 解析注意“否则”“除非”“但”等词。

双基限时练26

双基限时练(二十六) 1.已知下列四个等式: ①sin(α+β)=sin αcos β+cos αsin β; ②cos(α+β)=cos αcos β-sin αsin β; ③cos ? ?? ??π2+α=-sin α; ④tan(α-β)=tan α-tan β1+tan αtan β . 其中恒成立的等式有( ) A .2个 B .3个 C .4个 D .5个 解析 ①,②,③对任意角α,β恒成立,④中的α,β还要使正 切函数有意义. 答案 B 2.1-tan15°1+tan15° 的值为( ) A. 3 B.33 C .1 D .- 3 解析 原式=tan45°-tan15°1+tan45°tan15° =tan(45°-15°)=tan30°=33. 答案 B 3.设tan(α+β)=25,tan ? ????β-π4=14,则tan ? ?? ??α+π4等于( ) A.1328 B.1322 C.322 D.16 3.已知α,β为锐角,cos α=45,tan(α-β)=-13,则tan β的值为 ( )

A.13 B.139 C.1315 D.59 答案 B 4.已知tan α+tan β=2,tan(α+β)=4,则tan αtan β等于( ) A .2 B .1 C.12 D .4 解析 因为tan(α+β)=tan α+tan β 1-tan αtan β=21-tan αtan β =4,所以tan αtan β=12. 答案 C 5.若0<α<π2,0<β<π2,且tan α=17,tan β=34,则α+β等于( ) A.π6 B.π4 C.π3 D.3π4 解析 由已知可求得tan(α+β)=1. 又0<α+β<π,∴α+β=π4. 答案 B 6.已知tan α和tan ? ????π4-α是方程ax 2+bx +c =0的两个根,则a ,b ,c 的关系是( ) A .b =a +c B .2b =a +c C .c =b +a D .c =ab 解析 由韦达定理可知tan α+tan ? ????π4-α=-b a 且tan αtan ? ?? ??π4-a =

高二数学 双基限时练3

双基限时练(三) 1.设f ′(x 0)=0,则曲线y =f (x )在点(x 0,f (x 0))处的切线( ) A .不存在 B .与x 轴垂直 C .与x 轴平行 D .与x 轴平行或重合 答案 D 2.一木块沿某一斜面自由下滑,测得下滑的水平距离s 与时间t 之间的函数关系为s =18t 2,则当t =2时,此木块在水平方向的瞬时速 度为( ) A. 2 B. 1 C.12 D .14 解析 s ′=lim Δt →0 Δs Δt =lim Δt →0 18(t +Δt )2-18t 2Δt =lim Δt →0 14tΔt +18(Δt )2Δt =lim Δt →0 (14t +18Δt )=14t . ∴当t =2时,s ′=12. 答案 C 3.若曲线y =h (x )在点P (a ,h (a ))处切线方程为2x +y +1=0,则 ( ) A .h ′(a )<0 B .h ′(a )>0 C .h ′(a )=0 D .h ′(a )的符号不定 解析 由2x +y +1=0,得h ′(a )=-2<0. ∴h ′(a )<0. 答案 A

4.曲线y =9x 在点(3,3)处的切线方程的倾斜角α等于( ) A .45° B .60° C .135° D .120° 解析 k =y ′=lim Δx →0 Δy Δx =lim Δx →0 9x +Δx -9x Δx =lim Δx →0 -9x (x +Δx )=-9x 2. ∴当x =3时,tan α=-1.∴α=135°. 答案 C 5.在曲线y =x 2 上切线倾斜角为π4的点是( ) A .(0,0) B .(2,4) C .(14,116) D .(12,14) 解析 y ′=lim Δx →0 Δy Δx =lim Δx →0 (x +Δx )2-x 2Δx =lim Δx →0 2xΔx +(Δx )2Δx =lim Δx →0 (2x +Δx )=2x . 令2x =tan π4=1,∴x =12,y =14. 故所求的点是(12,14). 答案 D 6.已知曲线y =2x 2上一点A (2,8),则过点A 的切线的斜率为________. 解析 k =f ′(2)=lim Δx →0 2(2+Δx )2-2×22Δx

2019-2020年高中数学 双基限时练12 新人教A版必修3

2019-2020年高中数学双基限时练12 新人教A版必修3 1.问题:①有1000个乒乓球分别装在3个箱子内,其中红色箱子内有500个,蓝色箱子内有200个,黄色箱子内有300个,现从中抽取一个容量为100的样本;②从20名学生中选出3名参加座谈会. 方法:Ⅰ.简单随机抽样法Ⅱ.系统抽样法Ⅲ.分层抽样法.其中问题与方法能配对的是( ) A.①Ⅰ,②ⅡB.①Ⅲ,②Ⅰ C.①Ⅱ,②ⅢD.①Ⅲ,②Ⅱ 解析读题知①用分层抽样法,②用简单随机抽样法. 答案 B 2.一个单位有职工160人,其中有业务员104人,管理人员32人,后勤服务人员24人,要从中抽取一个容量为20的样本,用分层抽样方法抽出样本,则在20人的样本中管理人员人数为( ) A.3 B.4 C.12 D.7 解析由题意可得20 160 ×32=4. 答案 B 3.某地区为了解居民家庭生活状况,先把居民按所在行业分为几类,然后每个行业抽1 100的居民家庭进行调查,这种抽样是( ) A.简单随机抽样B.系统抽样 C.分层抽样D.分类抽样 答案 C 4.一个总体分为A,B两层,其个体数之比为,用分层抽样方法从总体中抽取一个容量为10的样本,则A层中抽取的样本个数为( ) A.8 B.6 C.4 D.2 答案 A 5.某大学数学系共有本科生5000人,其中一、二、三、四年级的学生数之比为4:3:2:1.要用分层抽样的方法从所有本科生中抽取一个容量为200的样本,则应抽三年级的学生( ) A.80人B.40人 C.60人D.20人

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北师大版高中英语必修二双基限时练12

高中英语学习材料 (灿若寒星*制作整理) 双基限时练(十二)Unit 5Lesson 3 Ⅰ.单词拼写 1.I'd like to ________ (辞职) my job because it's too hard for me. 答案quit 2.A famous ________ (音乐家) will perform in my city theatre tomorrow evening. 答案musician 3.His sister is such a ________ (美人) that many young men want to marry her. 答案beauty 4.He still hasn't found his own ________ (才能) in painting. 答案talent 5.Your ________ (发型) is not allowed in our school. 答案hairstyle 6.She enjoys playing the piano and hopes to be a ________ (钢琴家) when she grows up. 答案pianist 7.Mr. Smith has ________ (剃) all of his moustache and looks more handsome. 答案shaved 8.Plants get their supplies of food from the ground through their ________ (根).

答案roots 9.The business card is your ________ (身份), you must have one at all times. 答案identity 10.We can't judge a person only by his or her ________ (外貌).答案appearance Ⅱ.同义句转换 1.The little girl surprised the audience by performing a short play in English. →The little girl ________ the audience ________ by performing a short play in English. 答案made; surprised 2.He got too nervous to express himself clearly. →He got ________ nervous ________ he could not express himself clearly. 答案so; that 3.The bus arrived very late because the weather was bad. →The bus arrived very late ________ ________ the bad weather. 答案because of 4.Because of the terrible flood, farmers had a poor harvest that year. →________ ________ ________ ________ the terrible flood, farmers had a poor harvest that year. 答案As a result of 5.When he was only ten years old, the boy began to earn his living by selling newspapers.

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