MATLAB (1):
Simulink.
1.1
Matlab
1x1
Matlab
1
2
3
M
4
1.1.1
“
”[
]
A
.m aa.m
A Matlab aa
A
aa
A Matlab
1.1.2
Matlab
X
[ -1.3 sqrt(3) (1+2+3)*4/5 ]
X=
-1.300 1.732 4.800
X(2)ans=
1.7321
B=X(3)B=
4.8000
X(5)=abs(X(1))
X
X=
-1.3000 1.7321 4.800 0.0000 1.3000
X
A
A=[ 12345678
9 ]
A
A=[A[101112] ]
A=
1 2 3
4 5 6
7 8 9
10 11 12
“
”
B=A(1
3)
B=
1 2 3
4 5 6
7 8 9
1.1.3
Matlab“”Matlab
Matlab
1900/81
ans=
23.4568a=1900/81
a=
23.4568
“”
“”
“….”
S=1 –1/2 + 1/3 –1/4 + 1/5 -1/6 + 1/7….
-1/8 + 1/9 -1/10 + 1/11 -1/12;
1Matlab
19
2Matlab
a
A
inv
A
A
INV A
3pi
4inf S=1/0
S=inf
5NaN
inf
“Not a Number ”inf / inf
0 / 0
6
whos
1.1.4
*
/
\
^
Matlab
abs
sqrt
log
sin
cos
M
2+3=52-3= -1
2*3=62/3=0.66672\3=1.50002^3=8
8
2
3
6
3
2abs(-2)=2sqrt(9)=3sin(pi/3)=0.5log(1)=0
1.1.5
Matlab
i=sqrt(-1)
j=sqrt(-1)
Z=3 + 4*i
A=[1 2 3 4] + i*[5 67 8]
A=[1+5*i 2+6*i3+7*I 4+8*i]
1.1.6
format short
51/3 0.3333
format long
161/3 0.333333333333333
1.1.7 help
help inv
1.1.9
quit
exit
save.mat
1.1.8
clear
1.2
Matlab
1.2.1
A=[ 1
23
4
567
8
9 ]
A=1 2 34 5 6
7 8 9
B A ’
B=
1 4 7
2 5 8
3 6 9
Z
’
X [-1 0 2]
X ’
-102
A=
1 2 3
4 5 6
7 8 9C=
2 6 10
6 10 14
10 14 18
1.2.2
“
”“
”
C=A+B
1.2.3
C=
14 32 50
32 77 122
50 122 194 A=
1 2 3
4 5 6
7 8 9
B=
1 4 7
2 5 8
3 6 9
C=A*B
B=
1 4 7
2 5 8
3 6 9
A=
1 2 3
4 5 6
7 8 9
B=
1
2
3
C=2*A*B
C=
28
64
100
1.2.4
A\B Inv(A)*B
A/B
A*inv(B)
A
4
3
2
1
A
8
7
6
5
B
5.0
5.1
1
2
1
A
1.2.5
N
A
A^N
A
N
N
1
A^ N
A
N -1
A^N
N
A
N
1.2.6
A
inv (A)
1.3
1.3.1
“”
“”
1.3.2
.*
A B
A.*B
A
B
X=[1 2 3]; Y=[4 5 6];
Z=X.*Y Z=
4 10 18
A./B
A.\B :
Z=X.\Y
Z=
4.0000 2.5000 2.0000
Z=X./Y
Z=
0.2500 0.4000 0.5000
1.3.3
.^
X
Y
Z=X.^Y
Z=
1 3
2 729
X=[1 2 3]; Y=[4 5 6];
Z=X.^2
Z=
1 4 9
1.3.4
<
<=
>
>=
==
~=
1.3.5
abs
sqrt
sin
cos
tan
asin
acos
atan
sinh
cosh
tanh
exp
e
log10
10
real
imag
conj
fix
round
sign
rem
1.4
1.4.1
Matlab
Matlab
“
”
X
1
5
1
5
X
[1 2 3 4 5 ]
Y
1020
Y
[10 8 6 4 2 0]
X 0
2
6
Y X.^2[X ’
Y ’]
ans=
0 02 44 166 36
A(2
3
3
ans=
69
A(
2)‘
ans=
2 5 8
A=1 2 34 5 67 8 9
A(3
3)=A(1
3)+A(3
1)
A=1 2 34 5 6
7 8 10
A(2
3
ans=
4 5 6
7 8 10
1.4.1
eye(n
m)
n x m
eye(23)
ans=
1 0 0
0 1 0
eye(33)
ans=
1 0 0
0 1 0
0 0 1
eye(n
n)
n x n